Whakaoti i te x/x-3-1=4-x/x^2-3x

$$\frac{ x }{ x-3 } -1= \frac{ 4-x }{ { x }^{ 2 } -3x }$$

Whakaoti mō x

$$x=1$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe x ki tētahi o ngā uara 0,3 nā te kore tautuhi i te whakawehenga mā te kore. Me whakarea ngā taha e rua o te whārite ki te x\left(x-3\right), arā, te tauraro pātahi he tino iti rawa te kitea o x-3,x^{2}-3x.

$$xx+x\left(x-3\right)\left(-1\right)=4-x$$

Whakareatia te x ki te x, ka x^{2}.

$$x^{2}+x\left(x-3\right)\left(-1\right)=4-x$$

Whakamahia te āhuatanga tohatoha hei whakarea te x ki te x-3.

$$x^{2}+\left(x^{2}-3x\right)\left(-1\right)=4-x$$

Whakamahia te āhuatanga tohatoha hei whakarea te x^{2}-3x ki te -1.

$$x^{2}-x^{2}+3x=4-x$$

Pahekotia te x^{2} me -x^{2}, ka 0.

$$3x=4-x$$

Me tāpiri te x ki ngā taha e rua.

$$3x+x=4$$

Pahekotia te 3x me x, ka 4x.

$$4x=4$$

Whakawehea ngā taha e rua ki te 4.

$$x=\frac{4}{4}$$

Whakawehea te 4 ki te 4, kia riro ko 1.

$$x=1$$