Whakaoti i te x/2x-4

$$\frac{ x }{ 2x-4 }$$

Kimi Pārōnaki e ai ki x

$$-\frac{1}{\left(x-2\right)^{2}}$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Otinga

Mō ngā pānga e rua e taea ana te pārōnaki, ko te pārōnaki o te otinga o ngā pānga e rua ko te tauraro whakareatia ki te pārōnaki o te taurunga tango i te taurunga whakareatia ki te pārōnaki o te tauraro, ā, ka whakawehea te katoa ki te tauraro kua pūruatia.

$$\frac{\left(2x^{1}-4\right)\frac{\mathrm{d}}{\mathrm{d}x}(x^{1})-x^{1}\frac{\mathrm{d}}{\mathrm{d}x}(2x^{1}-4)}{\left(2x^{1}-4\right)^{2}}$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$\frac{\left(2x^{1}-4\right)x^{1-1}-x^{1}\times 2x^{1-1}}{\left(2x^{1}-4\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{\left(2x^{1}-4\right)x^{0}-x^{1}\times 2x^{0}}{\left(2x^{1}-4\right)^{2}}$$

Whakarohaina mā te āhuatanga tohatoha.

$$\frac{2x^{1}x^{0}-4x^{0}-x^{1}\times 2x^{0}}{\left(2x^{1}-4\right)^{2}}$$

Hei whakarea pū o te pūtake ōrite, tāpiri ana taupū.

$$\frac{2x^{1}-4x^{0}-2x^{1}}{\left(2x^{1}-4\right)^{2}}$$

Pahekotia ngā kīanga tau ōrite.

$$\frac{\left(2-2\right)x^{1}-4x^{0}}{\left(2x^{1}-4\right)^{2}}$$

Tango 2 mai i 2.

$$\frac{-4x^{0}}{\left(2x^{1}-4\right)^{2}}$$

Mō tētahi kupu t, t^{1}=t.

$$\frac{-4x^{0}}{\left(2x-4\right)^{2}}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$\frac{-4}{\left(2x-4\right)^{2}}$$

Aromātai

$$\frac{x}{2\left(x-2\right)}$$