Whakaoti i te x/16=40/x

$$\frac{ x }{ 16 } = \frac{ 40 }{ x }$$

Whakaoti mō x

$$x=8\sqrt{10}\approx 25.298221281$$

$$x=-8\sqrt{10}\approx -25.298221281$$

Ngā Upane mā te Kimi Pūtakerua

Tē taea kia ōrite te tāupe x ki 0 nā te kore tautuhi i te whakawehenga mā te kore. Me whakarea ngā taha e rua o te whārite ki te 16x, arā, te tauraro pātahi he tino iti rawa te kitea o 16,x.

$$xx=16\times 40$$

Whakareatia te x ki te x, ka x^{2}.

$$x^{2}=16\times 40$$

Whakareatia te 16 ki te 40, ka 640.

$$x^{2}=640$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=8\sqrt{10} x=-8\sqrt{10}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tē taea kia ōrite te tāupe x ki 0 nā te kore tautuhi i te whakawehenga mā te kore. Me whakarea ngā taha e rua o te whārite ki te 16x, arā, te tauraro pātahi he tino iti rawa te kitea o 16,x.

$$xx=16\times 40$$

Whakareatia te x ki te x, ka x^{2}.

$$x^{2}=16\times 40$$

Whakareatia te 16 ki te 40, ka 640.

$$x^{2}=640$$

Tangohia te 640 mai i ngā taha e rua.

$$x^{2}-640=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -640 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-640\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-640\right)}}{2}$$

Whakareatia -4 ki te -640.

$$x=\frac{0±\sqrt{2560}}{2}$$

Tuhia te pūtakerua o te 2560.

$$x=\frac{0±16\sqrt{10}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±16\sqrt{10}}{2} ina he tāpiri te ±.

$$x=8\sqrt{10}$$

Nā, me whakaoti te whārite x=\frac{0±16\sqrt{10}}{2} ina he tango te ±.

$$x=-8\sqrt{10}$$

Kua oti te whārite te whakatau.

$$x=8\sqrt{10} x=-8\sqrt{10}$$