Whakaoti i te A/x^+B/y^2=9

$$\frac{ A }{ { x }^{ } } + \frac{ B }{ { y }^{ 2 } } = 9$$

Whakaoti mō A

$$A=-\frac{Bx}{y^{2}}+9x$$

$$x\neq 0\text{ and }y\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me whakarea ngā taha e rua o te whārite ki te xy^{2}, arā, te tauraro pātahi he tino iti rawa te kitea o x^{1},y^{2}.

$$y^{2}A+xB=9xy^{2}$$

Tangohia te xB mai i ngā taha e rua.

$$y^{2}A=9xy^{2}-xB$$

He hanga arowhānui tō te whārite.

$$y^{2}A=9xy^{2}-Bx$$

Whakawehea ngā taha e rua ki te y^{2}.

$$\frac{y^{2}A}{y^{2}}=\frac{x\left(9y^{2}-B\right)}{y^{2}}$$

Mā te whakawehe ki te y^{2} ka wetekia te whakareanga ki te y^{2}.

$$A=\frac{x\left(9y^{2}-B\right)}{y^{2}}$$

Whakawehe x\left(9y^{2}-B\right) ki te y^{2}.

$$A=-\frac{Bx}{y^{2}}+9x$$

Whakaoti mō B

$$B=-\frac{\left(A-9x\right)y^{2}}{x}$$

$$x\neq 0\text{ and }y\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me whakarea ngā taha e rua o te whārite ki te xy^{2}, arā, te tauraro pātahi he tino iti rawa te kitea o x^{1},y^{2}.

$$y^{2}A+xB=9xy^{2}$$

Tangohia te y^{2}A mai i ngā taha e rua.

$$xB=9xy^{2}-y^{2}A$$

Whakaraupapatia anō ngā kīanga tau.

$$Bx=9xy^{2}-Ay^{2}$$

He hanga arowhānui tō te whārite.

$$xB=9xy^{2}-Ay^{2}$$

Whakawehea ngā taha e rua ki te x.

$$\frac{xB}{x}=\frac{\left(9x-A\right)y^{2}}{x}$$

Mā te whakawehe ki te x ka wetekia te whakareanga ki te x.

$$B=\frac{\left(9x-A\right)y^{2}}{x}$$