Whakaoti i te 90/x+90-40/x+40=02

$$\frac{ 90 }{ x+90 } - \frac{ 40 }{ x+40 } =02$$

Whakaoti mō x

$$x=0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe x ki tētahi o ngā uara -90,-40 nā te kore tautuhi i te whakawehenga mā te kore. Me whakarea ngā taha e rua o te whārite ki te \left(x+40\right)\left(x+90\right), arā, te tauraro pātahi he tino iti rawa te kitea o x+90,x+40.

$$\left(x+40\right)\times 90-\left(x+90\right)\times 40=0\times 2\left(x+40\right)\left(x+90\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te x+40 ki te 90.

$$90x+3600-\left(x+90\right)\times 40=0\times 2\left(x+40\right)\left(x+90\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te x+90 ki te 40.

$$90x+3600-\left(40x+3600\right)=0\times 2\left(x+40\right)\left(x+90\right)$$

Hei kimi i te tauaro o 40x+3600, kimihia te tauaro o ia taurangi.

$$90x+3600-40x-3600=0\times 2\left(x+40\right)\left(x+90\right)$$

Pahekotia te 90x me -40x, ka 50x.

$$50x+3600-3600=0\times 2\left(x+40\right)\left(x+90\right)$$

Tangohia te 3600 i te 3600, ka 0.

$$50x=0\times 2\left(x+40\right)\left(x+90\right)$$

Whakareatia te 0 ki te 2, ka 0.

$$50x=0\left(x+40\right)\left(x+90\right)$$

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$50x=0$$

He ōrite te hua o ngā tau e rua ki 0 ina 0 tētahi o rāua te iti rawa. Tātemea kāore te 50 e ōrite ki 0, me ōrite pū te x ki 0.

$$x=0$$