Whakaoti i te 8/sqrt{4-sqrt{2}}

$$\frac{ 8 }{ \sqrt{ 4 } - \sqrt{ 2 } }$$

Aromātai

$$4\sqrt{2}+8\approx 13.656854249$$

Ngā Upane Otinga

Tātaitia te pūtakerua o 4 kia tae ki 2.

$$\frac{8}{2-\sqrt{2}}$$

Whakangāwaritia te tauraro o \frac{8}{2-\sqrt{2}} mā te whakarea i te taurunga me te tauraro ki te 2+\sqrt{2}.

$$\frac{8\left(2+\sqrt{2}\right)}{\left(2-\sqrt{2}\right)\left(2+\sqrt{2}\right)}$$

Whakaarohia te \left(2-\sqrt{2}\right)\left(2+\sqrt{2}\right). Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{8\left(2+\sqrt{2}\right)}{2^{2}-\left(\sqrt{2}\right)^{2}}$$

Pūrua 2. Pūrua \sqrt{2}.

$$\frac{8\left(2+\sqrt{2}\right)}{4-2}$$

Tangohia te 2 i te 4, ka 2.

$$\frac{8\left(2+\sqrt{2}\right)}{2}$$

Whakawehea te 8\left(2+\sqrt{2}\right) ki te 2, kia riro ko 4\left(2+\sqrt{2}\right).

$$4\left(2+\sqrt{2}\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 4 ki te 2+\sqrt{2}.

$$8+4\sqrt{2}$$