Whakaoti i te 6x-3x/x^2-left(3xright)^2-x-3x/x+3x

$$\frac{ 6x-3x }{ { x }^{ 2 } - { \left(3x \right) }^{ 2 } } - \frac{ x-3x }{ x+3x }$$

Aromātai

$$\frac{1}{2}-\frac{3}{8x}$$

Ngā Hipanga Rongoā Poto

Pahekotia te 6x me -3x, ka 3x.

$$\frac{3x}{x^{2}-\left(3x\right)^{2}}-\frac{x-3x}{x+3x}$$

Whakarohaina te \left(3x\right)^{2}.

$$\frac{3x}{x^{2}-3^{2}x^{2}}-\frac{x-3x}{x+3x}$$

Tātaihia te 3 mā te pū o 2, kia riro ko 9.

$$\frac{3x}{x^{2}-9x^{2}}-\frac{x-3x}{x+3x}$$

Pahekotia te x^{2} me -9x^{2}, ka -8x^{2}.

$$\frac{3x}{-8x^{2}}-\frac{x-3x}{x+3x}$$

Me whakakore tahi te x i te taurunga me te tauraro.

$$\frac{3}{-8x}-\frac{x-3x}{x+3x}$$

Pahekotia te x me -3x, ka -2x.

$$\frac{3}{-8x}-\frac{-2x}{x+3x}$$

Pahekotia te x me 3x, ka 4x.

$$\frac{3}{-8x}-\frac{-2x}{4x}$$

Me whakakore tahi te 2x i te taurunga me te tauraro.

$$\frac{3}{-8x}-\frac{-1}{2}$$

Ka taea te hautanga \frac{-1}{2} te tuhi anō ko -\frac{1}{2} mā te tango i te tohu tōraro.

$$\frac{3}{-8x}-\left(-\frac{1}{2}\right)$$

Ko te tauaro o -\frac{1}{2} ko \frac{1}{2}.

$$\frac{3}{-8x}+\frac{1}{2}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o -8x me 2 ko 8x. Whakareatia \frac{3}{-8x} ki te \frac{-1}{-1}. Whakareatia \frac{1}{2} ki te \frac{4x}{4x}.

$$\frac{3\left(-1\right)}{8x}+\frac{4x}{8x}$$

Tā te mea he rite te tauraro o \frac{3\left(-1\right)}{8x} me \frac{4x}{8x}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{3\left(-1\right)+4x}{8x}$$

Mahia ngā whakarea i roto o 3\left(-1\right)+4x.

$$\frac{-3+4x}{8x}$$

Whakaroha

$$\frac{1}{2}-\frac{3}{8x}$$

Ngā Hipanga Rongoā Poto

Pahekotia te 6x me -3x, ka 3x.

$$\frac{3x}{x^{2}-\left(3x\right)^{2}}-\frac{x-3x}{x+3x}$$

Whakarohaina te \left(3x\right)^{2}.

$$\frac{3x}{x^{2}-3^{2}x^{2}}-\frac{x-3x}{x+3x}$$

Tātaihia te 3 mā te pū o 2, kia riro ko 9.

$$\frac{3x}{x^{2}-9x^{2}}-\frac{x-3x}{x+3x}$$

Pahekotia te x^{2} me -9x^{2}, ka -8x^{2}.

$$\frac{3x}{-8x^{2}}-\frac{x-3x}{x+3x}$$

Me whakakore tahi te x i te taurunga me te tauraro.

$$\frac{3}{-8x}-\frac{x-3x}{x+3x}$$

Pahekotia te x me -3x, ka -2x.

$$\frac{3}{-8x}-\frac{-2x}{x+3x}$$

Pahekotia te x me 3x, ka 4x.

$$\frac{3}{-8x}-\frac{-2x}{4x}$$

Me whakakore tahi te 2x i te taurunga me te tauraro.

$$\frac{3}{-8x}-\frac{-1}{2}$$

Ka taea te hautanga \frac{-1}{2} te tuhi anō ko -\frac{1}{2} mā te tango i te tohu tōraro.

$$\frac{3}{-8x}-\left(-\frac{1}{2}\right)$$

Ko te tauaro o -\frac{1}{2} ko \frac{1}{2}.

$$\frac{3}{-8x}+\frac{1}{2}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o -8x me 2 ko 8x. Whakareatia \frac{3}{-8x} ki te \frac{-1}{-1}. Whakareatia \frac{1}{2} ki te \frac{4x}{4x}.

$$\frac{3\left(-1\right)}{8x}+\frac{4x}{8x}$$

Tā te mea he rite te tauraro o \frac{3\left(-1\right)}{8x} me \frac{4x}{8x}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{3\left(-1\right)+4x}{8x}$$

Mahia ngā whakarea i roto o 3\left(-1\right)+4x.

$$\frac{-3+4x}{8x}$$