Whakaoti i te 6x-3x/left(7xright)^2-left(3xright)^2-3x-7x/3x+7x

$$\frac{ 6x-3x }{ { \left(7x \right) }^{ 2 } - { \left(3x \right) }^{ 2 } } - \frac{ 3x-7x }{ 3x+7x }$$

Aromātai

$$\frac{2}{5}+\frac{3}{40x}$$

Ngā Hipanga Rongoā Poto

Pahekotia te 6x me -3x, ka 3x.

$$\frac{3x}{\left(7x\right)^{2}-\left(3x\right)^{2}}-\frac{3x-7x}{3x+7x}$$

Whakarohaina te \left(7x\right)^{2}.

$$\frac{3x}{7^{2}x^{2}-\left(3x\right)^{2}}-\frac{3x-7x}{3x+7x}$$

Tātaihia te 7 mā te pū o 2, kia riro ko 49.

$$\frac{3x}{49x^{2}-\left(3x\right)^{2}}-\frac{3x-7x}{3x+7x}$$

Whakarohaina te \left(3x\right)^{2}.

$$\frac{3x}{49x^{2}-3^{2}x^{2}}-\frac{3x-7x}{3x+7x}$$

Tātaihia te 3 mā te pū o 2, kia riro ko 9.

$$\frac{3x}{49x^{2}-9x^{2}}-\frac{3x-7x}{3x+7x}$$

Pahekotia te 49x^{2} me -9x^{2}, ka 40x^{2}.

$$\frac{3x}{40x^{2}}-\frac{3x-7x}{3x+7x}$$

Me whakakore tahi te x i te taurunga me te tauraro.

$$\frac{3}{40x}-\frac{3x-7x}{3x+7x}$$

Pahekotia te 3x me -7x, ka -4x.

$$\frac{3}{40x}-\frac{-4x}{3x+7x}$$

Pahekotia te 3x me 7x, ka 10x.

$$\frac{3}{40x}-\frac{-4x}{10x}$$

Me whakakore tahi te 2x i te taurunga me te tauraro.

$$\frac{3}{40x}-\frac{-2}{5}$$

Ka taea te hautanga \frac{-2}{5} te tuhi anō ko -\frac{2}{5} mā te tango i te tohu tōraro.

$$\frac{3}{40x}-\left(-\frac{2}{5}\right)$$

Ko te tauaro o -\frac{2}{5} ko \frac{2}{5}.

$$\frac{3}{40x}+\frac{2}{5}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o 40x me 5 ko 40x. Whakareatia \frac{2}{5} ki te \frac{8x}{8x}.

$$\frac{3}{40x}+\frac{2\times 8x}{40x}$$

Tā te mea he rite te tauraro o \frac{3}{40x} me \frac{2\times 8x}{40x}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{3+2\times 8x}{40x}$$

Mahia ngā whakarea i roto o 3+2\times 8x.

$$\frac{3+16x}{40x}$$

Whakaroha

$$\frac{2}{5}+\frac{3}{40x}$$

Ngā Hipanga Rongoā Poto

Pahekotia te 6x me -3x, ka 3x.

$$\frac{3x}{\left(7x\right)^{2}-\left(3x\right)^{2}}-\frac{3x-7x}{3x+7x}$$

Whakarohaina te \left(7x\right)^{2}.

$$\frac{3x}{7^{2}x^{2}-\left(3x\right)^{2}}-\frac{3x-7x}{3x+7x}$$

Tātaihia te 7 mā te pū o 2, kia riro ko 49.

$$\frac{3x}{49x^{2}-\left(3x\right)^{2}}-\frac{3x-7x}{3x+7x}$$

Whakarohaina te \left(3x\right)^{2}.

$$\frac{3x}{49x^{2}-3^{2}x^{2}}-\frac{3x-7x}{3x+7x}$$

Tātaihia te 3 mā te pū o 2, kia riro ko 9.

$$\frac{3x}{49x^{2}-9x^{2}}-\frac{3x-7x}{3x+7x}$$

Pahekotia te 49x^{2} me -9x^{2}, ka 40x^{2}.

$$\frac{3x}{40x^{2}}-\frac{3x-7x}{3x+7x}$$

Me whakakore tahi te x i te taurunga me te tauraro.

$$\frac{3}{40x}-\frac{3x-7x}{3x+7x}$$

Pahekotia te 3x me -7x, ka -4x.

$$\frac{3}{40x}-\frac{-4x}{3x+7x}$$

Pahekotia te 3x me 7x, ka 10x.

$$\frac{3}{40x}-\frac{-4x}{10x}$$

Me whakakore tahi te 2x i te taurunga me te tauraro.

$$\frac{3}{40x}-\frac{-2}{5}$$

Ka taea te hautanga \frac{-2}{5} te tuhi anō ko -\frac{2}{5} mā te tango i te tohu tōraro.

$$\frac{3}{40x}-\left(-\frac{2}{5}\right)$$

Ko te tauaro o -\frac{2}{5} ko \frac{2}{5}.

$$\frac{3}{40x}+\frac{2}{5}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o 40x me 5 ko 40x. Whakareatia \frac{2}{5} ki te \frac{8x}{8x}.

$$\frac{3}{40x}+\frac{2\times 8x}{40x}$$

Tā te mea he rite te tauraro o \frac{3}{40x} me \frac{2\times 8x}{40x}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{3+2\times 8x}{40x}$$

Mahia ngā whakarea i roto o 3+2\times 8x.

$$\frac{3+16x}{40x}$$