Whakaoti i te 5x+8/x+5geq2

$$\frac{ 5x+8 }{ x+5 } \geq 2$$

Whakaoti mō x

$$x\in (-\infty,-5)\cup [\frac{2}{3},\infty)$$

Ngā Upane Otinga

Kāore e taea a te tauraro x+5 te numa kore nā te mea kāore te rituatanga mā te kore e tautuhi. E rua ngā kēhi.

$$x+5>0 x+5<0$$

Whakaarohia te kēhi i ngā wā kei te tōrunga a x+5. Neke atu a 5 ki te taha matau.

$$x>-5$$

Kāore te tōrite tuatahi e whakarerekē te aronga ina e whakarea ana mā x+5 mō x+5>0.

$$5x+8\geq 2\left(x+5\right)$$

Whakarea te katoa o te taha matau.

$$5x+8\geq 2x+10$$

Neke atu ngā kīanga tau e whai ana i x ki te taha mauī me ētahi atu kupu katoa ki te taha matau.

$$5x-2x\geq -8+10$$

Pahekotia ngā kīanga tau ōrite.

$$3x\geq 2$$

Whakawehea ngā taha e rua ki te 3. I te mea he tōrunga te 3, kāore e huri te ahunga koreōrite.

$$x\geq \frac{2}{3}$$

Tēnā, me whakaarohia te tauira ina e tōraro a x+5. Neke atu a 5 ki te taha matau.

$$x<-5$$

E whakarerekē ana te aronga o te tōrite tuatahi hei ngā wā e whakarea ana a x+5 mō x+5<0.

$$5x+8\leq 2\left(x+5\right)$$

Whakarea te katoa o te taha matau.

$$5x+8\leq 2x+10$$

Neke atu ngā kīanga tau e whai ana i x ki te taha mauī me ētahi atu kupu katoa ki te taha matau.

$$5x-2x\leq -8+10$$

Pahekotia ngā kīanga tau ōrite.

$$3x\leq 2$$

Whakawehea ngā taha e rua ki te 3. I te mea he tōrunga te 3, kāore e huri te ahunga koreōrite.

$$x\leq \frac{2}{3}$$

Whakaarohia te herenga x<-5 e tautuhi ana ki runga.

$$x<-5$$

Ko te otinga whakamutunga ko te whakakotahi i ngā otinga kua whiwhi.

$$x\in (-\infty,-5)\cup [\frac{2}{3},\infty)$$