Whakaoti i te 4-x/x+1<1

$$\frac{ 4-x }{ x+1 } < 1$$

Whakaoti mō x

$$x\in \left(-\infty,-1\right)\cup \left(\frac{3}{2},\infty\right)$$

Ngā Upane Otinga

Kāore e taea a te tauraro x+1 te numa kore nā te mea kāore te rituatanga mā te kore e tautuhi. E rua ngā kēhi.

$$x+1>0 x+1<0$$

Whakaarohia te kēhi i ngā wā kei te tōrunga a x+1. Neke atu a 1 ki te taha matau.

$$x>-1$$

Kāore te tōrite tuatahi e whakarerekē te aronga ina e whakarea ana mā x+1 mō x+1>0.

$$4-x<x+1$$

Neke atu ngā kīanga tau e whai ana i x ki te taha mauī me ētahi atu kupu katoa ki te taha matau.

$$-x-x<-4+1$$

Pahekotia ngā kīanga tau ōrite.

$$-2x<-3$$

Whakawehea ngā taha e rua ki te -2. I te mea he tōraro a -2, ka huri te ahunga koreōrite.

$$x>\frac{3}{2}$$

Whakaarohia te herenga x>-1 e tautuhi ana ki runga. E noho ōrite te toenga.

$$x>\frac{3}{2}$$

Tēnā, me whakaarohia te tauira ina e tōraro a x+1. Neke atu a 1 ki te taha matau.

$$x<-1$$

E whakarerekē ana te aronga o te tōrite tuatahi hei ngā wā e whakarea ana a x+1 mō x+1<0.

$$4-x>x+1$$

Neke atu ngā kīanga tau e whai ana i x ki te taha mauī me ētahi atu kupu katoa ki te taha matau.

$$-x-x>-4+1$$

Pahekotia ngā kīanga tau ōrite.

$$-2x>-3$$

Whakawehea ngā taha e rua ki te -2. I te mea he tōraro a -2, ka huri te ahunga koreōrite.

$$x<\frac{3}{2}$$

Whakaarohia te herenga x<-1 e tautuhi ana ki runga.

$$x<-1$$

Ko te otinga whakamutunga ko te whakakotahi i ngā otinga kua whiwhi.

$$x\in \left(-\infty,-1\right)\cup \left(\frac{3}{2},\infty\right)$$