Whakaoti i te 3x-4/5+1/8leq6x+7/8-x+1

$$\frac{ 3x-4 }{ 5 } + \frac{ 1 }{ 8 } \leq \frac{ 6x+7 }{ 8 } -x+1$$

Whakaoti mō x

$$x\leq 3$$

Ngā Upane Otinga

Me whakarea ngā taha e rua o te whārite ki te 40, arā, te tauraro pātahi he tino iti rawa te kitea o 5,8. I te mea he tōrunga te 40, kāore e huri te ahunga koreōrite.

$$8\left(3x-4\right)+5\leq 5\left(6x+7\right)-40x+40$$

Whakamahia te āhuatanga tohatoha hei whakarea te 8 ki te 3x-4.

$$24x-32+5\leq 5\left(6x+7\right)-40x+40$$

Tāpirihia te -32 ki te 5, ka -27.

$$24x-27\leq 5\left(6x+7\right)-40x+40$$

Whakamahia te āhuatanga tohatoha hei whakarea te 5 ki te 6x+7.

$$24x-27\leq 30x+35-40x+40$$

Pahekotia te 30x me -40x, ka -10x.

$$24x-27\leq -10x+35+40$$

Tāpirihia te 35 ki te 40, ka 75.

$$24x-27\leq -10x+75$$

Me tāpiri te 10x ki ngā taha e rua.

$$24x-27+10x\leq 75$$

Pahekotia te 24x me 10x, ka 34x.

$$34x-27\leq 75$$

Me tāpiri te 27 ki ngā taha e rua.

$$34x\leq 75+27$$

Tāpirihia te 75 ki te 27, ka 102.

$$34x\leq 102$$

Whakawehea ngā taha e rua ki te 34. I te mea he tōrunga te 34, kāore e huri te ahunga koreōrite.

$$x\leq \frac{102}{34}$$

Whakawehea te 102 ki te 34, kia riro ko 3.

$$x\leq 3$$