Whakaoti i te 3x-2/2-4x-3/4=3x+1/8

$$\frac{ 3x-2 }{ 2 } - \frac{ 4x-3 }{ 4 } = \frac{ 3x+1 }{ 8 }$$

Whakaoti mō x

$$x=3$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me whakarea ngā taha e rua o te whārite ki te 8, arā, te tauraro pātahi he tino iti rawa te kitea o 2,4,8.

$$4\left(3x-2\right)-2\left(4x-3\right)=3x+1$$

Whakamahia te āhuatanga tohatoha hei whakarea te 4 ki te 3x-2.

$$12x-8-2\left(4x-3\right)=3x+1$$

Whakamahia te āhuatanga tohatoha hei whakarea te -2 ki te 4x-3.

$$12x-8-8x+6=3x+1$$

Pahekotia te 12x me -8x, ka 4x.

$$4x-8+6=3x+1$$

Tāpirihia te -8 ki te 6, ka -2.

$$4x-2=3x+1$$

Tangohia te 3x mai i ngā taha e rua.

$$4x-2-3x=1$$

Pahekotia te 4x me -3x, ka x.

$$x-2=1$$

Me tāpiri te 2 ki ngā taha e rua.

$$x=1+2$$

Tāpirihia te 1 ki te 2, ka 3.

$$x=3$$