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\frac{3\left(1+\sqrt{5}\right)}{\left(1-\sqrt{5}\right)\left(1+\sqrt{5}\right)}
Whakangāwaritia te tauraro o \frac{3}{1-\sqrt{5}} mā te whakarea i te taurunga me te tauraro ki te 1+\sqrt{5}.
\frac{3\left(1+\sqrt{5}\right)}{1^{2}-\left(\sqrt{5}\right)^{2}}
Whakaarohia te \left(1-\sqrt{5}\right)\left(1+\sqrt{5}\right). Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{3\left(1+\sqrt{5}\right)}{1-5}
Pūrua 1. Pūrua \sqrt{5}.
\frac{3\left(1+\sqrt{5}\right)}{-4}
Tangohia te 5 i te 1, ka -4.
\frac{3+3\sqrt{5}}{-4}
Whakamahia te āhuatanga tohatoha hei whakarea te 3 ki te 1+\sqrt{5}.