Whakaoti i te 20/sqrt{6-sqrt{2}}

$$\frac{ 20 }{ \sqrt{ 6 } - \sqrt{ 2 } }$$

Aromātai

$$5\left(\sqrt{2}+\sqrt{6}\right)\approx 19.318516526$$

Ngā Upane Otinga

Whakangāwaritia te tauraro o \frac{20}{\sqrt{6}-\sqrt{2}} mā te whakarea i te taurunga me te tauraro ki te \sqrt{6}+\sqrt{2}.

$$\frac{20\left(\sqrt{6}+\sqrt{2}\right)}{\left(\sqrt{6}-\sqrt{2}\right)\left(\sqrt{6}+\sqrt{2}\right)}$$

Whakaarohia te \left(\sqrt{6}-\sqrt{2}\right)\left(\sqrt{6}+\sqrt{2}\right). Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{20\left(\sqrt{6}+\sqrt{2}\right)}{\left(\sqrt{6}\right)^{2}-\left(\sqrt{2}\right)^{2}}$$

Pūrua \sqrt{6}. Pūrua \sqrt{2}.

$$\frac{20\left(\sqrt{6}+\sqrt{2}\right)}{6-2}$$

Tangohia te 2 i te 6, ka 4.

$$\frac{20\left(\sqrt{6}+\sqrt{2}\right)}{4}$$

Whakawehea te 20\left(\sqrt{6}+\sqrt{2}\right) ki te 4, kia riro ko 5\left(\sqrt{6}+\sqrt{2}\right).

$$5\left(\sqrt{6}+\sqrt{2}\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 5 ki te \sqrt{6}+\sqrt{2}.

$$5\sqrt{6}+5\sqrt{2}$$