Whakaoti i te 2x^2/1-6x

$$\frac{ 2 { x }^{ 2 } }{ 1-6x }$$

Kimi Pārōnaki e ai ki x

$$-\frac{4x\left(3x-1\right)}{\left(6x-1\right)^{2}}$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Otinga

Mō ngā pānga e rua e taea ana te pārōnaki, ko te pārōnaki o te otinga o ngā pānga e rua ko te tauraro whakareatia ki te pārōnaki o te taurunga tango i te taurunga whakareatia ki te pārōnaki o te tauraro, ā, ka whakawehea te katoa ki te tauraro kua pūruatia.

$$\frac{\left(-6x^{1}+1\right)\frac{\mathrm{d}}{\mathrm{d}x}(2x^{2})-2x^{2}\frac{\mathrm{d}}{\mathrm{d}x}(-6x^{1}+1)}{\left(-6x^{1}+1\right)^{2}}$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$\frac{\left(-6x^{1}+1\right)\times 2\times 2x^{2-1}-2x^{2}\left(-6\right)x^{1-1}}{\left(-6x^{1}+1\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{\left(-6x^{1}+1\right)\times 4x^{1}-2x^{2}\left(-6\right)x^{0}}{\left(-6x^{1}+1\right)^{2}}$$

Whakarohaina mā te āhuatanga tohatoha.

$$\frac{-6x^{1}\times 4x^{1}+4x^{1}-2x^{2}\left(-6\right)x^{0}}{\left(-6x^{1}+1\right)^{2}}$$

Hei whakarea pū o te pūtake ōrite, tāpiri ana taupū.

$$\frac{-6\times 4x^{1+1}+4x^{1}-2\left(-6\right)x^{2}}{\left(-6x^{1}+1\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{-24x^{2}+4x^{1}-\left(-12x^{2}\right)}{\left(-6x^{1}+1\right)^{2}}$$

Pahekotia ngā kīanga tau ōrite.

$$\frac{\left(-24-\left(-12\right)\right)x^{2}+4x^{1}}{\left(-6x^{1}+1\right)^{2}}$$

Tango -12 mai i -24.

$$\frac{-12x^{2}+4x^{1}}{\left(-6x^{1}+1\right)^{2}}$$

Tauwehea te 4x.

$$\frac{4x\left(-3x^{1}+x^{0}\right)}{\left(-6x^{1}+1\right)^{2}}$$

Mō tētahi kupu t, t^{1}=t.

$$\frac{4x\left(-3x+x^{0}\right)}{\left(-6x+1\right)^{2}}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$\frac{4x\left(-3x+1\right)}{\left(-6x+1\right)^{2}}$$

Aromātai

$$\frac{2x^{2}}{1-6x}$$