Whakaoti i te 2*4/4^2+35/2-2x-2/-2^2+35/2

$$\frac{ 2 \times 4 }{ { 4 }^{ 2 } +3 } \frac{ 5 }{ 2 } - \frac{ 2x-2 }{ - { 2 }^{ 2 } +3 } \frac{ 5 }{ 2 }$$

Aromātai

$$5x-\frac{75}{19}$$

Ngā Upane Otinga

Whakareatia te 2 ki te 4, ka 8.

$$\frac{8}{4^{2}+3}\times \frac{5}{2}-\frac{2x-2}{-2^{2}+3}\times \frac{5}{2}$$

Tātaihia te 4 mā te pū o 2, kia riro ko 16.

$$\frac{8}{16+3}\times \frac{5}{2}-\frac{2x-2}{-2^{2}+3}\times \frac{5}{2}$$

Tāpirihia te 16 ki te 3, ka 19.

$$\frac{8}{19}\times \frac{5}{2}-\frac{2x-2}{-2^{2}+3}\times \frac{5}{2}$$

Me whakarea te \frac{8}{19} ki te \frac{5}{2} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\frac{8\times 5}{19\times 2}-\frac{2x-2}{-2^{2}+3}\times \frac{5}{2}$$

Mahia ngā whakarea i roto i te hautanga \frac{8\times 5}{19\times 2}.

$$\frac{40}{38}-\frac{2x-2}{-2^{2}+3}\times \frac{5}{2}$$

Whakahekea te hautanga \frac{40}{38} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$\frac{20}{19}-\frac{2x-2}{-2^{2}+3}\times \frac{5}{2}$$

Tātaihia te 2 mā te pū o 2, kia riro ko 4.

$$\frac{20}{19}-\frac{2x-2}{-4+3}\times \frac{5}{2}$$

Tāpirihia te -4 ki te 3, ka -1.

$$\frac{20}{19}-\frac{2x-2}{-1}\times \frac{5}{2}$$

Ko te mea whakawehea ki te -1 ka hōmai i tōna kōaro. Hei kimi i te tauaro o 2x-2, kimihia te tauaro o ia taurangi.

$$\frac{20}{19}-\left(-2x-\left(-2\right)\right)\times \frac{5}{2}$$

Whakamahia te āhuatanga tohatoha hei whakarea te -2x-\left(-2\right) ki te \frac{5}{2}.

$$\frac{20}{19}-\left(-2x\times \frac{5}{2}+\left(-\left(-2\right)\right)\times \frac{5}{2}\right)$$

Whakareatia -2 ki te \frac{5}{2}.

$$\frac{20}{19}-\left(-5x+\left(-\left(-2\right)\right)\times \frac{5}{2}\right)$$

Ko te tauaro o -2 ko 2.

$$\frac{20}{19}-\left(-5x+2\times \frac{5}{2}\right)$$

Me whakakore te 2 me te 2.

$$\frac{20}{19}-\left(-5x+5\right)$$

Hei kimi i te tauaro o -5x+5, kimihia te tauaro o ia taurangi.

$$\frac{20}{19}-\left(-5x\right)-5$$

Ko te tauaro o -5x ko 5x.

$$\frac{20}{19}+5x-5$$

Me tahuri te 5 ki te hautau \frac{95}{19}.

$$\frac{20}{19}+5x-\frac{95}{19}$$

Tā te mea he rite te tauraro o \frac{20}{19} me \frac{95}{19}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{20-95}{19}+5x$$

Tangohia te 95 i te 20, ka -75.

$$-\frac{75}{19}+5x$$

Whakaroha

$$5x-\frac{75}{19}$$

Ngā Upane Otinga

Whakareatia te 2 ki te 4, ka 8.

$$\frac{8}{4^{2}+3}\times \frac{5}{2}-\frac{2x-2}{-2^{2}+3}\times \frac{5}{2}$$

Tātaihia te 4 mā te pū o 2, kia riro ko 16.

$$\frac{8}{16+3}\times \frac{5}{2}-\frac{2x-2}{-2^{2}+3}\times \frac{5}{2}$$

Tāpirihia te 16 ki te 3, ka 19.

$$\frac{8}{19}\times \frac{5}{2}-\frac{2x-2}{-2^{2}+3}\times \frac{5}{2}$$

Me whakarea te \frac{8}{19} ki te \frac{5}{2} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\frac{8\times 5}{19\times 2}-\frac{2x-2}{-2^{2}+3}\times \frac{5}{2}$$

Mahia ngā whakarea i roto i te hautanga \frac{8\times 5}{19\times 2}.

$$\frac{40}{38}-\frac{2x-2}{-2^{2}+3}\times \frac{5}{2}$$

Whakahekea te hautanga \frac{40}{38} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$\frac{20}{19}-\frac{2x-2}{-2^{2}+3}\times \frac{5}{2}$$

Tātaihia te 2 mā te pū o 2, kia riro ko 4.

$$\frac{20}{19}-\frac{2x-2}{-4+3}\times \frac{5}{2}$$

Tāpirihia te -4 ki te 3, ka -1.

$$\frac{20}{19}-\frac{2x-2}{-1}\times \frac{5}{2}$$

Ko te mea whakawehea ki te -1 ka hōmai i tōna kōaro. Hei kimi i te tauaro o 2x-2, kimihia te tauaro o ia taurangi.

$$\frac{20}{19}-\left(-2x-\left(-2\right)\right)\times \frac{5}{2}$$

Whakamahia te āhuatanga tohatoha hei whakarea te -2x-\left(-2\right) ki te \frac{5}{2}.

$$\frac{20}{19}-\left(-2x\times \frac{5}{2}+\left(-\left(-2\right)\right)\times \frac{5}{2}\right)$$

Whakareatia -2 ki te \frac{5}{2}.

$$\frac{20}{19}-\left(-5x+\left(-\left(-2\right)\right)\times \frac{5}{2}\right)$$

Ko te tauaro o -2 ko 2.

$$\frac{20}{19}-\left(-5x+2\times \frac{5}{2}\right)$$

Me whakakore te 2 me te 2.

$$\frac{20}{19}-\left(-5x+5\right)$$

Hei kimi i te tauaro o -5x+5, kimihia te tauaro o ia taurangi.

$$\frac{20}{19}-\left(-5x\right)-5$$

Ko te tauaro o -5x ko 5x.

$$\frac{20}{19}+5x-5$$

Me tahuri te 5 ki te hautau \frac{95}{19}.

$$\frac{20}{19}+5x-\frac{95}{19}$$

Tā te mea he rite te tauraro o \frac{20}{19} me \frac{95}{19}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{20-95}{19}+5x$$

Tangohia te 95 i te 20, ka -75.

$$-\frac{75}{19}+5x$$