Whakaoti i te 2/3(x+7)-x/4leq1/2(3-x)+x/6

$$\frac{ 2 }{ 3 } (x+7)- \frac{ x }{ 4 } \leq \frac{ 1 }{ 2 } (3-x)+ \frac{ x }{ 6 }$$

Whakaoti mō x

$$x\leq -\frac{38}{9}$$

Ngā Upane Otinga

Me whakarea ngā taha e rua o te whārite ki te 12, arā, te tauraro pātahi he tino iti rawa te kitea o 3,4,2,6. I te mea he tōrunga te 12, kāore e huri te ahunga koreōrite.

$$8\left(x+7\right)-3x\leq 6\left(3-x\right)+2x$$

Whakamahia te āhuatanga tohatoha hei whakarea te 8 ki te x+7.

$$8x+56-3x\leq 6\left(3-x\right)+2x$$

Pahekotia te 8x me -3x, ka 5x.

$$5x+56\leq 6\left(3-x\right)+2x$$

Whakamahia te āhuatanga tohatoha hei whakarea te 6 ki te 3-x.

$$5x+56\leq 18-6x+2x$$

Pahekotia te -6x me 2x, ka -4x.

$$5x+56\leq 18-4x$$

Me tāpiri te 4x ki ngā taha e rua.

$$5x+56+4x\leq 18$$

Pahekotia te 5x me 4x, ka 9x.

$$9x+56\leq 18$$

Tangohia te 56 mai i ngā taha e rua.

$$9x\leq 18-56$$

Tangohia te 56 i te 18, ka -38.

$$9x\leq -38$$

Whakawehea ngā taha e rua ki te 9. I te mea he tōrunga te 9, kāore e huri te ahunga koreōrite.

$$x\leq -\frac{38}{9}$$