Whakaoti i te 16/3+x=4/3-x

$$\frac{ 16 }{ 3+x } = \frac{ 4 }{ 3-x }$$

Whakaoti mō x

$$x = \frac{9}{5} = 1\frac{4}{5} = 1.8$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe x ki tētahi o ngā uara -3,3 nā te kore tautuhi i te whakawehenga mā te kore. Me whakarea ngā taha e rua o te whārite ki te \left(x-3\right)\left(x+3\right), arā, te tauraro pātahi he tino iti rawa te kitea o 3+x,3-x.

$$\left(x-3\right)\times 16=-\left(3+x\right)\times 4$$

Whakamahia te āhuatanga tohatoha hei whakarea te x-3 ki te 16.

$$16x-48=-\left(3+x\right)\times 4$$

Whakareatia te -1 ki te 4, ka -4.

$$16x-48=-4\left(3+x\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te -4 ki te 3+x.

$$16x-48=-12-4x$$

Me tāpiri te 4x ki ngā taha e rua.

$$16x-48+4x=-12$$

Pahekotia te 16x me 4x, ka 20x.

$$20x-48=-12$$

Me tāpiri te 48 ki ngā taha e rua.

$$20x=-12+48$$

Tāpirihia te -12 ki te 48, ka 36.

$$20x=36$$

Whakawehea ngā taha e rua ki te 20.

$$x=\frac{36}{20}$$

Whakahekea te hautanga \frac{36}{20} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 4.

$$x=\frac{9}{5}$$