Whakaoti i te 13c^9d^10/-26c^9d

$$\frac{ 13 { c }^{ 9 } { d }^{ 10 } }{ -26 { c }^{ 9 } d }$$

Aromātai

$$-\frac{d^{9}}{2}$$

Ngā Upane e Whakamahi ana i te Āhuatanga o te Otinga o ngā Pū

Whakamahia ngā ture taupū hei whakarūnā i te kīanga.

$$\frac{13^{1}c^{9}d^{10}}{\left(-26\right)^{1}c^{9}d^{1}}$$

Hei whakawehe i ngā pū o te pūtake kotahi, tangohia te taupū o te tauraro mai i te taupū o te taurunga.

$$\frac{13^{1}}{\left(-26\right)^{1}}c^{9-9}d^{10-1}$$

Tango 9 mai i 9.

$$\frac{13^{1}}{\left(-26\right)^{1}}c^{0}d^{10-1}$$

Mō tētahi tau a mahue te 0, a^{0}=1.

$$\frac{13^{1}}{\left(-26\right)^{1}}d^{10-1}$$

Tango 1 mai i 10.

$$\frac{13^{1}}{\left(-26\right)^{1}}d^{9}$$

Whakahekea te hautanga \frac{13}{-26} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 13.

$$-\frac{1}{2}d^{9}$$

Kimi Pārōnaki e ai ki d

$$-\frac{9d^{8}}{2}$$

Ngā Upane e Whakamahi ana i te Tautuhinga o te Pārōnaki

Me whakakore tahi te 13dc^{9} i te taurunga me te tauraro.

$$\frac{\mathrm{d}}{\mathrm{d}d}(\frac{d^{9}}{-2})$$

Ko te pārōnaki o ax^{n} ko nax^{n-1}.

$$9\left(-\frac{1}{2}\right)d^{9-1}$$

Whakareatia 9 ki te -\frac{1}{2}.

$$-\frac{9}{2}d^{9-1}$$

Tango 1 mai i 9.

$$-\frac{9}{2}d^{8}$$