Whakaoti i te 1/x-6divx^2

$$\frac{ 1 }{ x-6 } \div { x }^{ 2 }$$

Aromātai

$$\frac{1}{\left(x-6\right)x^{2}}$$

Ngā Upane Otinga

Tuhia te \frac{\frac{1}{x-6}}{x^{2}} hei hautanga kotahi.

$$\frac{1}{\left(x-6\right)x^{2}}$$

Whakamahia te āhuatanga tohatoha hei whakarea te x-6 ki te x^{2}.

$$\frac{1}{x^{3}-6x^{2}}$$

Kimi Pārōnaki e ai ki x

$$\frac{3\left(4-x\right)}{\left(x-6\right)^{2}x^{3}}$$

Ngā Upane e Whakamahi ana i te Ture Mekameka

Tuhia te \frac{\frac{1}{x-6}}{x^{2}} hei hautanga kotahi.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{1}{\left(x-6\right)x^{2}})$$

Whakamahia te āhuatanga tohatoha hei whakarea te x-6 ki te x^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{1}{x^{3}-6x^{2}})$$

Mēnā ko F te hanganga o ngā pānga e rua e taea ana te pārōnaki f\left(u\right) me u=g\left(x\right), arā, mēnā ko F\left(x\right)=f\left(g\left(x\right)\right), ko te pārōnaki o F te pārōnaki o f e ai ki u whakareatia te pārōnaki o g e ai ki x, arā, \frac{\mathrm{d}}{\mathrm{d}x}(F)\left(x\right)=\frac{\mathrm{d}}{\mathrm{d}x}(f)\left(g\left(x\right)\right)\frac{\mathrm{d}}{\mathrm{d}x}(g)\left(x\right).

$$-\left(x^{3}-6x^{2}\right)^{-1-1}\frac{\mathrm{d}}{\mathrm{d}x}(x^{3}-6x^{2})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$-\left(x^{3}-6x^{2}\right)^{-2}\left(3x^{3-1}+2\left(-6\right)x^{2-1}\right)$$

Whakarūnātia.

$$\left(x^{3}-6x^{2}\right)^{-2}\left(-3x^{2}+12x^{1}\right)$$

Mō tētahi kupu t, t^{1}=t.

$$\left(x^{3}-6x^{2}\right)^{-2}\left(-3x^{2}+12x\right)$$