Whakaoti i te 1/x-2+2

$$\frac{ 1 }{ x-2 } +2$$

Aromātai

$$\frac{2x-3}{x-2}$$

Ngā Hipanga Rongoā Poto

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia 2 ki te \frac{x-2}{x-2}.

$$\frac{1}{x-2}+\frac{2\left(x-2\right)}{x-2}$$

Tā te mea he rite te tauraro o \frac{1}{x-2} me \frac{2\left(x-2\right)}{x-2}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{1+2\left(x-2\right)}{x-2}$$

Mahia ngā whakarea i roto o 1+2\left(x-2\right).

$$\frac{1+2x-4}{x-2}$$

Whakakotahitia ngā kupu rite i 1+2x-4.

$$\frac{-3+2x}{x-2}$$

Kimi Pārōnaki e ai ki x

$$-\frac{1}{\left(x-2\right)^{2}}$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Otinga

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia 2 ki te \frac{x-2}{x-2}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{1}{x-2}+\frac{2\left(x-2\right)}{x-2})$$

Tā te mea he rite te tauraro o \frac{1}{x-2} me \frac{2\left(x-2\right)}{x-2}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{1+2\left(x-2\right)}{x-2})$$

Mahia ngā whakarea i roto o 1+2\left(x-2\right).

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{1+2x-4}{x-2})$$

Whakakotahitia ngā kupu rite i 1+2x-4.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{-3+2x}{x-2})$$

Mō ngā pānga e rua e taea ana te pārōnaki, ko te pārōnaki o te otinga o ngā pānga e rua ko te tauraro whakareatia ki te pārōnaki o te taurunga tango i te taurunga whakareatia ki te pārōnaki o te tauraro, ā, ka whakawehea te katoa ki te tauraro kua pūruatia.

$$\frac{\left(x^{1}-2\right)\frac{\mathrm{d}}{\mathrm{d}x}(2x^{1}-3)-\left(2x^{1}-3\right)\frac{\mathrm{d}}{\mathrm{d}x}(x^{1}-2)}{\left(x^{1}-2\right)^{2}}$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$\frac{\left(x^{1}-2\right)\times 2x^{1-1}-\left(2x^{1}-3\right)x^{1-1}}{\left(x^{1}-2\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{\left(x^{1}-2\right)\times 2x^{0}-\left(2x^{1}-3\right)x^{0}}{\left(x^{1}-2\right)^{2}}$$

Whakarohaina mā te āhuatanga tohatoha.

$$\frac{x^{1}\times 2x^{0}-2\times 2x^{0}-\left(2x^{1}x^{0}-3x^{0}\right)}{\left(x^{1}-2\right)^{2}}$$

Hei whakarea pū o te pūtake ōrite, tāpiri ana taupū.

$$\frac{2x^{1}-2\times 2x^{0}-\left(2x^{1}-3x^{0}\right)}{\left(x^{1}-2\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{2x^{1}-4x^{0}-\left(2x^{1}-3x^{0}\right)}{\left(x^{1}-2\right)^{2}}$$

Tangohia ngā taiapa kāore i te hiahiatia.

$$\frac{2x^{1}-4x^{0}-2x^{1}-\left(-3x^{0}\right)}{\left(x^{1}-2\right)^{2}}$$

Pahekotia ngā kīanga tau ōrite.

$$\frac{\left(2-2\right)x^{1}+\left(-4-\left(-3\right)\right)x^{0}}{\left(x^{1}-2\right)^{2}}$$

Tangohia te 2 i 2 me te -3 i te -4.

$$\frac{-x^{0}}{\left(x^{1}-2\right)^{2}}$$

Mō tētahi kupu t, t^{1}=t.

$$\frac{-x^{0}}{\left(x-2\right)^{2}}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$\frac{-1}{\left(x-2\right)^{2}}$$