Whakaoti i te 1/3+3x+2y-sqrt{4z}+2^2=0

$$\frac{ 1 }{ 3 } +3x+2y- \sqrt{ 4z } + { 2 }^{ 2 } =0$$

Whakaoti mō x

$$x=-\frac{2y}{3}+\frac{2\sqrt{z}}{3}-\frac{13}{9}$$

$$z\geq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tātaihia te 2 mā te pū o 2, kia riro ko 4.

$$\frac{1}{3}+3x+2y-\sqrt{4z}+4=0$$

Tāpirihia te \frac{1}{3} ki te 4, ka \frac{13}{3}.

$$\frac{13}{3}+3x+2y-\sqrt{4z}=0$$

Tangohia te \frac{13}{3} mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$3x+2y-\sqrt{4z}=-\frac{13}{3}$$

Tangohia te 2y mai i ngā taha e rua.

$$3x-\sqrt{4z}=-\frac{13}{3}-2y$$

Me tāpiri te \sqrt{4z} ki ngā taha e rua.

$$3x=-\frac{13}{3}-2y+\sqrt{4z}$$

He hanga arowhānui tō te whārite.

$$3x=-2y+\sqrt{4z}-\frac{13}{3}$$

Whakawehea ngā taha e rua ki te 3.

$$\frac{3x}{3}=\frac{-2y+2\sqrt{z}-\frac{13}{3}}{3}$$

Mā te whakawehe ki te 3 ka wetekia te whakareanga ki te 3.

$$x=\frac{-2y+2\sqrt{z}-\frac{13}{3}}{3}$$

Whakawehe -\frac{13}{3}-2y+2\sqrt{z} ki te 3.

$$x=-\frac{2y}{3}+\frac{2\sqrt{z}}{3}-\frac{13}{9}$$

Whakaoti mō y

$$y=-\frac{3x}{2}+\sqrt{z}-\frac{13}{6}$$

$$z\geq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tātaihia te 2 mā te pū o 2, kia riro ko 4.

$$\frac{1}{3}+3x+2y-\sqrt{4z}+4=0$$

Tāpirihia te \frac{1}{3} ki te 4, ka \frac{13}{3}.

$$\frac{13}{3}+3x+2y-\sqrt{4z}=0$$

Tangohia te \frac{13}{3} mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$3x+2y-\sqrt{4z}=-\frac{13}{3}$$

Tangohia te 3x mai i ngā taha e rua.

$$2y-\sqrt{4z}=-\frac{13}{3}-3x$$

Me tāpiri te \sqrt{4z} ki ngā taha e rua.

$$2y=-\frac{13}{3}-3x+\sqrt{4z}$$

He hanga arowhānui tō te whārite.

$$2y=-3x+\sqrt{4z}-\frac{13}{3}$$

Whakawehea ngā taha e rua ki te 2.

$$\frac{2y}{2}=\frac{-3x+2\sqrt{z}-\frac{13}{3}}{2}$$

Mā te whakawehe ki te 2 ka wetekia te whakareanga ki te 2.

$$y=\frac{-3x+2\sqrt{z}-\frac{13}{3}}{2}$$

Whakawehe -\frac{13}{3}-3x+2\sqrt{z} ki te 2.

$$y=-\frac{3x}{2}+\sqrt{z}-\frac{13}{6}$$