Whakaoti i te 1/2x+(6-x)=7/4

$$\frac{ 1 }{ 2 } x+(6-x) = \frac{ 7 }{ 4 }$$

Whakaoti mō x

$$x = \frac{17}{2} = 8\frac{1}{2} = 8.5$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Pahekotia te \frac{1}{2}x me -x, ka -\frac{1}{2}x.

$$-\frac{1}{2}x+6=\frac{7}{4}$$

Tangohia te 6 mai i ngā taha e rua.

$$-\frac{1}{2}x=\frac{7}{4}-6$$

Me tahuri te 6 ki te hautau \frac{24}{4}.

$$-\frac{1}{2}x=\frac{7}{4}-\frac{24}{4}$$

Tā te mea he rite te tauraro o \frac{7}{4} me \frac{24}{4}, me tango rāua mā te tango i ō raua taurunga.

$$-\frac{1}{2}x=\frac{7-24}{4}$$

Tangohia te 24 i te 7, ka -17.

$$-\frac{1}{2}x=-\frac{17}{4}$$

Me whakarea ngā taha e rua ki te -2, te tau utu o -\frac{1}{2}.

$$x=-\frac{17}{4}\left(-2\right)$$

Tuhia te -\frac{17}{4}\left(-2\right) hei hautanga kotahi.

$$x=\frac{-17\left(-2\right)}{4}$$

Whakareatia te -17 ki te -2, ka 34.

$$x=\frac{34}{4}$$

Whakahekea te hautanga \frac{34}{4} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$x=\frac{17}{2}$$