Whakaoti i te 1/2x+(6-x)=11/4

$$\frac{ 1 }{ 2 } x+(6-x) = \frac{ 11 }{ 4 }$$

Whakaoti mō x

$$x = \frac{13}{2} = 6\frac{1}{2} = 6.5$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Pahekotia te \frac{1}{2}x me -x, ka -\frac{1}{2}x.

$$-\frac{1}{2}x+6=\frac{11}{4}$$

Tangohia te 6 mai i ngā taha e rua.

$$-\frac{1}{2}x=\frac{11}{4}-6$$

Me tahuri te 6 ki te hautau \frac{24}{4}.

$$-\frac{1}{2}x=\frac{11}{4}-\frac{24}{4}$$

Tā te mea he rite te tauraro o \frac{11}{4} me \frac{24}{4}, me tango rāua mā te tango i ō raua taurunga.

$$-\frac{1}{2}x=\frac{11-24}{4}$$

Tangohia te 24 i te 11, ka -13.

$$-\frac{1}{2}x=-\frac{13}{4}$$

Me whakarea ngā taha e rua ki te -2, te tau utu o -\frac{1}{2}.

$$x=-\frac{13}{4}\left(-2\right)$$

Tuhia te -\frac{13}{4}\left(-2\right) hei hautanga kotahi.

$$x=\frac{-13\left(-2\right)}{4}$$

Whakareatia te -13 ki te -2, ka 26.

$$x=\frac{26}{4}$$

Whakahekea te hautanga \frac{26}{4} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$x=\frac{13}{2}$$