Whakaoti i te 1/x^2-2x-1/x^2-4x+4

$$\frac{ 1 }{ { x }^{ 2 } -2x } - \frac{ 1 }{ { x }^{ 2 } -4x+4 }$$

Aromātai

$$-\frac{2}{x\left(x-2\right)^{2}}$$

Ngā Hipanga Rongoā Poto

Tauwehea te x^{2}-2x. Tauwehea te x^{2}-4x+4.

$$\frac{1}{x\left(x-2\right)}-\frac{1}{\left(x-2\right)^{2}}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o x\left(x-2\right) me \left(x-2\right)^{2} ko x\left(x-2\right)^{2}. Whakareatia \frac{1}{x\left(x-2\right)} ki te \frac{x-2}{x-2}. Whakareatia \frac{1}{\left(x-2\right)^{2}} ki te \frac{x}{x}.

$$\frac{x-2}{x\left(x-2\right)^{2}}-\frac{x}{x\left(x-2\right)^{2}}$$

Tā te mea he rite te tauraro o \frac{x-2}{x\left(x-2\right)^{2}} me \frac{x}{x\left(x-2\right)^{2}}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{x-2-x}{x\left(x-2\right)^{2}}$$

Whakakotahitia ngā kupu rite i x-2-x.

$$\frac{-2}{x\left(x-2\right)^{2}}$$

Whakarohaina te x\left(x-2\right)^{2}.

$$\frac{-2}{x^{3}-4x^{2}+4x}$$

Kimi Pārōnaki e ai ki x

$$\frac{2\left(3x-2\right)}{x^{2}\left(x-2\right)^{3}}$$