Whakaoti i te 1/x^2-2x-1/x^2+2x

$$\frac{ 1 }{ { x }^{ 2 } -2x } - \frac{ 1 }{ { x }^{ 2 } +2x }$$

Aromātai

$$\frac{4}{x\left(x^{2}-4\right)}$$

Ngā Hipanga Rongoā Poto

Tauwehea te x^{2}-2x. Tauwehea te x^{2}+2x.

$$\frac{1}{x\left(x-2\right)}-\frac{1}{x\left(x+2\right)}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o x\left(x-2\right) me x\left(x+2\right) ko x\left(x-2\right)\left(x+2\right). Whakareatia \frac{1}{x\left(x-2\right)} ki te \frac{x+2}{x+2}. Whakareatia \frac{1}{x\left(x+2\right)} ki te \frac{x-2}{x-2}.

$$\frac{x+2}{x\left(x-2\right)\left(x+2\right)}-\frac{x-2}{x\left(x-2\right)\left(x+2\right)}$$

Tā te mea he rite te tauraro o \frac{x+2}{x\left(x-2\right)\left(x+2\right)} me \frac{x-2}{x\left(x-2\right)\left(x+2\right)}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{x+2-\left(x-2\right)}{x\left(x-2\right)\left(x+2\right)}$$

Mahia ngā whakarea i roto o x+2-\left(x-2\right).

$$\frac{x+2-x+2}{x\left(x-2\right)\left(x+2\right)}$$

Whakakotahitia ngā kupu rite i x+2-x+2.

$$\frac{4}{x\left(x-2\right)\left(x+2\right)}$$

Whakarohaina te x\left(x-2\right)\left(x+2\right).

$$\frac{4}{x^{3}-4x}$$

Kimi Pārōnaki e ai ki x

$$\frac{4\left(4-3x^{2}\right)}{\left(x\left(x^{2}-4\right)\right)^{2}}$$