Whakaoti i te 02/40+2x=0376/2left(108+xright)

$$\frac{ 02 }{ 40+2x } = \frac{ 0376 }{ 2 \left( 108+x \right) }$$

Whakaoti mō x (complex solution)

$$x\in \mathrm{C}\setminus -20,-108$$

Ngā Upane Otinga

Tē taea kia ōrite te tāupe x ki tētahi o ngā uara -108,-20 nā te kore tautuhi i te whakawehenga mā te kore. Me whakarea ngā taha e rua o te whārite ki te 2\left(x+20\right)\left(x+108\right), arā, te tauraro pātahi he tino iti rawa te kitea o 40+2x,2\left(108+x\right).

$$\left(x+108\right)\times 0\times 2=\left(x+20\right)\times 0\times 376$$

Whakareatia te 0 ki te 2, ka 0.

$$\left(x+108\right)\times 0=\left(x+20\right)\times 0\times 376$$

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$0=\left(x+20\right)\times 0\times 376$$

Whakareatia te 0 ki te 376, ka 0.

$$0=\left(x+20\right)\times 0$$

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$0=0$$

Whakatauritea te 0 me te 0.

$$\text{true}$$

He pono tēnei mō tētahi x ahakoa.

$$x\in \mathrm{C}$$

Tē taea kia ōrite te tāupe x ki tētahi o ngā uara -108,-20.

$$x\in \mathrm{C}\setminus -108,-20$$

Whakaoti mō x

$$x\in \mathrm{R}\setminus -20,-108$$

Ngā Upane Otinga

Tē taea kia ōrite te tāupe x ki tētahi o ngā uara -108,-20 nā te kore tautuhi i te whakawehenga mā te kore. Me whakarea ngā taha e rua o te whārite ki te 2\left(x+20\right)\left(x+108\right), arā, te tauraro pātahi he tino iti rawa te kitea o 40+2x,2\left(108+x\right).

$$\left(x+108\right)\times 0\times 2=\left(x+20\right)\times 0\times 376$$

Whakareatia te 0 ki te 2, ka 0.

$$\left(x+108\right)\times 0=\left(x+20\right)\times 0\times 376$$

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$0=\left(x+20\right)\times 0\times 376$$

Whakareatia te 0 ki te 376, ka 0.

$$0=\left(x+20\right)\times 0$$

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$0=0$$

Whakatauritea te 0 me te 0.

$$\text{true}$$

He pono tēnei mō tētahi x ahakoa.

$$x\in \mathrm{R}$$

Tē taea kia ōrite te tāupe x ki tētahi o ngā uara -108,-20.

$$x\in \mathrm{R}\setminus -108,-20$$