Whakaoti i te -6/x^2-4x+3-3/3-x-4/x-1

$$\frac{ -6 }{ { x }^{ 2 } -4x+3 } - \frac{ 3 }{ 3-x } - \frac{ 4 }{ x-1 }$$

Aromātai

$$-\frac{1}{x-1}$$

Ngā Hipanga Rongoā Poto

Tauwehea te x^{2}-4x+3.

$$\frac{-6}{\left(x-3\right)\left(x-1\right)}-\frac{3}{3-x}-\frac{4}{x-1}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o \left(x-3\right)\left(x-1\right) me 3-x ko \left(x-3\right)\left(x-1\right). Whakareatia \frac{3}{3-x} ki te \frac{-\left(x-1\right)}{-\left(x-1\right)}.

$$\frac{-6}{\left(x-3\right)\left(x-1\right)}-\frac{3\left(-1\right)\left(x-1\right)}{\left(x-3\right)\left(x-1\right)}-\frac{4}{x-1}$$

Tā te mea he rite te tauraro o \frac{-6}{\left(x-3\right)\left(x-1\right)} me \frac{3\left(-1\right)\left(x-1\right)}{\left(x-3\right)\left(x-1\right)}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{-6-3\left(-1\right)\left(x-1\right)}{\left(x-3\right)\left(x-1\right)}-\frac{4}{x-1}$$

Mahia ngā whakarea i roto o -6-3\left(-1\right)\left(x-1\right).

$$\frac{-6+3x-3}{\left(x-3\right)\left(x-1\right)}-\frac{4}{x-1}$$

Whakakotahitia ngā kupu rite i -6+3x-3.

$$\frac{-9+3x}{\left(x-3\right)\left(x-1\right)}-\frac{4}{x-1}$$

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea i roto o \frac{-9+3x}{\left(x-3\right)\left(x-1\right)}.

$$\frac{3\left(x-3\right)}{\left(x-3\right)\left(x-1\right)}-\frac{4}{x-1}$$

Me whakakore tahi te x-3 i te taurunga me te tauraro.

$$\frac{3}{x-1}-\frac{4}{x-1}$$

Tā te mea he rite te tauraro o \frac{3}{x-1} me \frac{4}{x-1}, me tango rāua mā te tango i ō raua taurunga. Tangohia te 4 i te 3, ka -1.

$$\frac{-1}{x-1}$$

Kimi Pārōnaki e ai ki x

$$\frac{1}{\left(x-1\right)^{2}}$$