Whakaoti i te -3-3i/-3+i

$$\frac{ -3-3i }{ -3+i }$$

Aromātai

$$\frac{3}{5}+\frac{6}{5}i=0.6+1.2i$$

Ngā Upane Otinga

Whakareatia te taurunga me te tauraro ki te haumi hiato o te tauraro, -3-i.

$$\frac{\left(-3-3i\right)\left(-3-i\right)}{\left(-3+i\right)\left(-3-i\right)}$$

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{\left(-3-3i\right)\left(-3-i\right)}{\left(-3\right)^{2}-i^{2}}$$

Hei tōna tikanga, ko te i^{2} ko -1. Tātaitia te tauraro.

$$\frac{\left(-3-3i\right)\left(-3-i\right)}{10}$$

Me whakarea ngā tau matatini -3-3i me -3-i pēnā i te whakarea huarua.

$$\frac{-3\left(-3\right)-3\left(-i\right)-3i\left(-3\right)-3\left(-1\right)i^{2}}{10}$$

Hei tōna tikanga, ko te i^{2} ko -1.

$$\frac{-3\left(-3\right)-3\left(-i\right)-3i\left(-3\right)-3\left(-1\right)\left(-1\right)}{10}$$

Mahia ngā whakarea i roto o -3\left(-3\right)-3\left(-i\right)-3i\left(-3\right)-3\left(-1\right)\left(-1\right).

$$\frac{9+3i+9i-3}{10}$$

Whakakotahitia ngā wāhi tūturu me ngā wāhi pōhewa ki 9+3i+9i-3.

$$\frac{9-3+\left(3+9\right)i}{10}$$

Mahia ngā tāpiri i roto o 9-3+\left(3+9\right)i.

$$\frac{6+12i}{10}$$

Whakawehea te 6+12i ki te 10, kia riro ko \frac{3}{5}+\frac{6}{5}i.

$$\frac{3}{5}+\frac{6}{5}i$$

Wāhi Tūturu

$$\frac{3}{5} = 0.6$$

Ngā Upane Otinga

Me whakarea te taurunga me te tauraro o \frac{-3-3i}{-3+i} ki te haumi hiato o te tauraro, -3-i.

$$Re(\frac{\left(-3-3i\right)\left(-3-i\right)}{\left(-3+i\right)\left(-3-i\right)})$$

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$Re(\frac{\left(-3-3i\right)\left(-3-i\right)}{\left(-3\right)^{2}-i^{2}})$$

Hei tōna tikanga, ko te i^{2} ko -1. Tātaitia te tauraro.

$$Re(\frac{\left(-3-3i\right)\left(-3-i\right)}{10})$$

Me whakarea ngā tau matatini -3-3i me -3-i pēnā i te whakarea huarua.

$$Re(\frac{-3\left(-3\right)-3\left(-i\right)-3i\left(-3\right)-3\left(-1\right)i^{2}}{10})$$

Hei tōna tikanga, ko te i^{2} ko -1.

$$Re(\frac{-3\left(-3\right)-3\left(-i\right)-3i\left(-3\right)-3\left(-1\right)\left(-1\right)}{10})$$

Mahia ngā whakarea i roto o -3\left(-3\right)-3\left(-i\right)-3i\left(-3\right)-3\left(-1\right)\left(-1\right).

$$Re(\frac{9+3i+9i-3}{10})$$

Whakakotahitia ngā wāhi tūturu me ngā wāhi pōhewa ki 9+3i+9i-3.

$$Re(\frac{9-3+\left(3+9\right)i}{10})$$

Mahia ngā tāpiri i roto o 9-3+\left(3+9\right)i.

$$Re(\frac{6+12i}{10})$$

Whakawehea te 6+12i ki te 10, kia riro ko \frac{3}{5}+\frac{6}{5}i.

$$Re(\frac{3}{5}+\frac{6}{5}i)$$

Ko te wāhi tūturu o \frac{3}{5}+\frac{6}{5}i ko \frac{3}{5}.

$$\frac{3}{5}$$