Whakaoti i te x^4/4-x^3+x^2+1+c=0

$$\frac{ { x }^{ 4 } }{ 4 } - { x }^{ 3 } + { x }^{ 2 } +1+c=0$$

Whakaoti mō c

$$c=-\frac{\left(x^{2}+2\right)^{2}}{4}+x^{3}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia ngā taha e rua o te whārite ki te 4.

$$x^{4}-4x^{3}+4x^{2}+4+4c=0$$

Tangohia te x^{4} mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-4x^{3}+4x^{2}+4+4c=-x^{4}$$

Me tāpiri te 4x^{3} ki ngā taha e rua.

$$4x^{2}+4+4c=-x^{4}+4x^{3}$$

Tangohia te 4x^{2} mai i ngā taha e rua.

$$4+4c=-x^{4}+4x^{3}-4x^{2}$$

Tangohia te 4 mai i ngā taha e rua.

$$4c=-x^{4}+4x^{3}-4x^{2}-4$$

Whakawehea ngā taha e rua ki te 4.

$$\frac{4c}{4}=\frac{-\left(x^{2}+2\right)^{2}+4x^{3}}{4}$$

Mā te whakawehe ki te 4 ka wetekia te whakareanga ki te 4.

$$c=\frac{-\left(x^{2}+2\right)^{2}+4x^{3}}{4}$$

Whakawehe 4x^{3}-\left(x^{2}+2\right)^{2} ki te 4.

$$c=-\frac{\left(x^{2}+2\right)^{2}}{4}+x^{3}$$