Whakaoti i te x^2+6/2x-10-x/2=x/x-5

$$\frac{ { x }^{ 2 } +6 }{ 2x-10 } - \frac{ x }{ 2 } = \frac{ x }{ x-5 }$$

Whakaoti mō x

$$x=-2$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe x ki 5 nā te kore tautuhi i te whakawehenga mā te kore. Me whakarea ngā taha e rua o te whārite ki te 2\left(x-5\right), arā, te tauraro pātahi he tino iti rawa te kitea o 2x-10,2,x-5.

$$x^{2}+6-\left(x-5\right)x=2x$$

Whakamahia te āhuatanga tohatoha hei whakarea te x-5 ki te x.

$$x^{2}+6-\left(x^{2}-5x\right)=2x$$

Hei kimi i te tauaro o x^{2}-5x, kimihia te tauaro o ia taurangi.

$$x^{2}+6-x^{2}+5x=2x$$

Pahekotia te x^{2} me -x^{2}, ka 0.

$$6+5x=2x$$

Tangohia te 2x mai i ngā taha e rua.

$$6+5x-2x=0$$

Pahekotia te 5x me -2x, ka 3x.

$$6+3x=0$$

Tangohia te 6 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$3x=-6$$

Whakawehea ngā taha e rua ki te 3.

$$x=\frac{-6}{3}$$

Whakawehea te -6 ki te 3, kia riro ko -2.

$$x=-2$$