Whakaoti i te 1^3/1^2=15^2/x^2

$$\frac{ { 1 }^{ 3 } }{ { 1 }^{ 2 } } = \frac{ { 15 }^{ 2 } }{ { x }^{ 2 } }$$

Whakaoti mō x

$$x=15$$

$$x=-15$$

Ngā Hipanga Whakamahi Rerekētanga o ngā Pūrua

Tē taea kia ōrite te tāupe x ki 0 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te x^{2}.

$$x^{2}\times 1^{3}=15^{2}$$

Tātaihia te 1 mā te pū o 3, kia riro ko 1.

$$x^{2}\times 1=15^{2}$$

Tātaihia te 15 mā te pū o 2, kia riro ko 225.

$$x^{2}\times 1=225$$

Tangohia te 225 mai i ngā taha e rua.

$$x^{2}\times 1-225=0$$

Whakaraupapatia anō ngā kīanga tau.

$$x^{2}-225=0$$

Whakaarohia te x^{2}-225. Tuhia anō te x^{2}-225 hei x^{2}-15^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(x-15\right)\left(x+15\right)=0$$

Hei kimi otinga whārite, me whakaoti te x-15=0 me te x+15=0.

$$x=15 x=-15$$

Ngā Upane mā te Kimi Pūtakerua

Tē taea kia ōrite te tāupe x ki 0 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te x^{2}.

$$x^{2}\times 1^{3}=15^{2}$$

Tātaihia te 1 mā te pū o 3, kia riro ko 1.

$$x^{2}\times 1=15^{2}$$

Tātaihia te 15 mā te pū o 2, kia riro ko 225.

$$x^{2}\times 1=225$$

Whakawehea ngā taha e rua ki te 1.

$$x^{2}=225$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=15 x=-15$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tē taea kia ōrite te tāupe x ki 0 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te x^{2}.

$$x^{2}\times 1^{3}=15^{2}$$

Tātaihia te 1 mā te pū o 3, kia riro ko 1.

$$x^{2}\times 1=15^{2}$$

Tātaihia te 15 mā te pū o 2, kia riro ko 225.

$$x^{2}\times 1=225$$

Tangohia te 225 mai i ngā taha e rua.

$$x^{2}\times 1-225=0$$

Whakaraupapatia anō ngā kīanga tau.

$$x^{2}-225=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -225 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-225\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-225\right)}}{2}$$

Whakareatia -4 ki te -225.

$$x=\frac{0±\sqrt{900}}{2}$$

Tuhia te pūtakerua o te 900.

$$x=\frac{0±30}{2}$$

Nā, me whakaoti te whārite x=\frac{0±30}{2} ina he tāpiri te ±. Whakawehe 30 ki te 2.

$$x=15$$

Nā, me whakaoti te whārite x=\frac{0±30}{2} ina he tango te ±. Whakawehe -30 ki te 2.

$$x=-15$$

Kua oti te whārite te whakatau.

$$x=15 x=-15$$