Whakaoti i te frac{{left(sqrt{x^4}right)}^{2}*{left(sqrt{x^8}right)}^{2}{left(sqrt{x^14}right)}^{2}}{{left(sqrt{x^4}right)}^{2}*{left(sqrt{{x}^8}right)}^2*{left(sqrt{{x}^2}right)}^2}

$$\frac{ { \left( \sqrt{ { x }^{ 4 } } \right) }^{ 2 } \times { \left( \sqrt{ { x }^{ 8 } } \right) }^{ 2 } { \left( \sqrt{ { x }^{ 14 } } \right) }^{ 2 } }{ { \left( \sqrt{ { x }^{ 4 } } \right) }^{ 2 } \times { \left( \sqrt{ { x }^{ 8 } } \right) }^{ 2 } \times { \left( \sqrt{ { x }^{ 2 } } \right) }^{ 2 } }$$

Aromātai

$$x^{12}$$

Ngā Upane Otinga

Me whakakore tahi te \left(\sqrt{x^{4}}\right)^{2}\left(\sqrt{x^{8}}\right)^{2} i te taurunga me te tauraro.

$$\frac{\left(\sqrt{x^{14}}\right)^{2}}{\left(\sqrt{x^{2}}\right)^{2}}$$

Tātaihia te \sqrt{x^{14}} mā te pū o 2, kia riro ko x^{14}.

$$\frac{x^{14}}{\left(\sqrt{x^{2}}\right)^{2}}$$

Tātaihia te \sqrt{x^{2}} mā te pū o 2, kia riro ko x^{2}.

$$\frac{x^{14}}{x^{2}}$$

Me whakakore tahi te x^{2} i te taurunga me te tauraro.

$$x^{12}$$

Kimi Pārōnaki e ai ki x

$$12x^{11}$$

Ngā Upane e Whakamahi ana i te Tautuhinga o te Pārōnaki

Me whakakore tahi te \left(\sqrt{x^{4}}\right)^{2}\left(\sqrt{x^{8}}\right)^{2} i te taurunga me te tauraro.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{\left(\sqrt{x^{14}}\right)^{2}}{\left(\sqrt{x^{2}}\right)^{2}})$$

Tātaihia te \sqrt{x^{14}} mā te pū o 2, kia riro ko x^{14}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{x^{14}}{\left(\sqrt{x^{2}}\right)^{2}})$$

Tātaihia te \sqrt{x^{2}} mā te pū o 2, kia riro ko x^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{x^{14}}{x^{2}})$$

Me whakakore tahi te x^{2} i te taurunga me te tauraro.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x^{12})$$

Ko te pārōnaki o ax^{n} ko nax^{n-1}.

$$12x^{12-1}$$

Tango 1 mai i 12.

$$12x^{11}$$