Whakaoti i te x+4/x+3-x-3/x+4/frac{14{x^2+7x+12}}

$$\frac{ \frac{ x+4 }{ x+3 } - \frac{ x-3 }{ x+4 } }{ \frac{ 14 }{ { x }^{ 2 } +7x+12 } }$$

Aromātai

$$\frac{4x}{7}+\frac{25}{14}$$

Ngā Hipanga Rongoā Poto

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o x+3 me x+4 ko \left(x+3\right)\left(x+4\right). Whakareatia \frac{x+4}{x+3} ki te \frac{x+4}{x+4}. Whakareatia \frac{x-3}{x+4} ki te \frac{x+3}{x+3}.

$$\frac{\frac{\left(x+4\right)\left(x+4\right)}{\left(x+3\right)\left(x+4\right)}-\frac{\left(x-3\right)\left(x+3\right)}{\left(x+3\right)\left(x+4\right)}}{\frac{14}{x^{2}+7x+12}}$$

Tā te mea he rite te tauraro o \frac{\left(x+4\right)\left(x+4\right)}{\left(x+3\right)\left(x+4\right)} me \frac{\left(x-3\right)\left(x+3\right)}{\left(x+3\right)\left(x+4\right)}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{\frac{\left(x+4\right)\left(x+4\right)-\left(x-3\right)\left(x+3\right)}{\left(x+3\right)\left(x+4\right)}}{\frac{14}{x^{2}+7x+12}}$$

Mahia ngā whakarea i roto o \left(x+4\right)\left(x+4\right)-\left(x-3\right)\left(x+3\right).

$$\frac{\frac{x^{2}+4x+4x+16-x^{2}-3x+3x+9}{\left(x+3\right)\left(x+4\right)}}{\frac{14}{x^{2}+7x+12}}$$

Whakakotahitia ngā kupu rite i x^{2}+4x+4x+16-x^{2}-3x+3x+9.

$$\frac{\frac{8x+25}{\left(x+3\right)\left(x+4\right)}}{\frac{14}{x^{2}+7x+12}}$$

Whakawehe \frac{8x+25}{\left(x+3\right)\left(x+4\right)} ki te \frac{14}{x^{2}+7x+12} mā te whakarea \frac{8x+25}{\left(x+3\right)\left(x+4\right)} ki te tau huripoki o \frac{14}{x^{2}+7x+12}.

$$\frac{\left(8x+25\right)\left(x^{2}+7x+12\right)}{\left(x+3\right)\left(x+4\right)\times 14}$$

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea.

$$\frac{\left(x+3\right)\left(x+4\right)\left(8x+25\right)}{14\left(x+3\right)\left(x+4\right)}$$

Me whakakore tahi te \left(x+3\right)\left(x+4\right) i te taurunga me te tauraro.

$$\frac{8x+25}{14}$$

Whakaroha

$$\frac{4x}{7}+\frac{25}{14}$$

Ngā Hipanga Rongoā Poto

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o x+3 me x+4 ko \left(x+3\right)\left(x+4\right). Whakareatia \frac{x+4}{x+3} ki te \frac{x+4}{x+4}. Whakareatia \frac{x-3}{x+4} ki te \frac{x+3}{x+3}.

$$\frac{\frac{\left(x+4\right)\left(x+4\right)}{\left(x+3\right)\left(x+4\right)}-\frac{\left(x-3\right)\left(x+3\right)}{\left(x+3\right)\left(x+4\right)}}{\frac{14}{x^{2}+7x+12}}$$

Tā te mea he rite te tauraro o \frac{\left(x+4\right)\left(x+4\right)}{\left(x+3\right)\left(x+4\right)} me \frac{\left(x-3\right)\left(x+3\right)}{\left(x+3\right)\left(x+4\right)}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{\frac{\left(x+4\right)\left(x+4\right)-\left(x-3\right)\left(x+3\right)}{\left(x+3\right)\left(x+4\right)}}{\frac{14}{x^{2}+7x+12}}$$

Mahia ngā whakarea i roto o \left(x+4\right)\left(x+4\right)-\left(x-3\right)\left(x+3\right).

$$\frac{\frac{x^{2}+4x+4x+16-x^{2}-3x+3x+9}{\left(x+3\right)\left(x+4\right)}}{\frac{14}{x^{2}+7x+12}}$$

Whakakotahitia ngā kupu rite i x^{2}+4x+4x+16-x^{2}-3x+3x+9.

$$\frac{\frac{8x+25}{\left(x+3\right)\left(x+4\right)}}{\frac{14}{x^{2}+7x+12}}$$

Whakawehe \frac{8x+25}{\left(x+3\right)\left(x+4\right)} ki te \frac{14}{x^{2}+7x+12} mā te whakarea \frac{8x+25}{\left(x+3\right)\left(x+4\right)} ki te tau huripoki o \frac{14}{x^{2}+7x+12}.

$$\frac{\left(8x+25\right)\left(x^{2}+7x+12\right)}{\left(x+3\right)\left(x+4\right)\times 14}$$

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea.

$$\frac{\left(x+3\right)\left(x+4\right)\left(8x+25\right)}{14\left(x+3\right)\left(x+4\right)}$$

Me whakakore tahi te \left(x+3\right)\left(x+4\right) i te taurunga me te tauraro.

$$\frac{8x+25}{14}$$