Whakaoti i te y-xy/3=-4+2y/-2

$$\frac { y - x y } { 3 } = - \frac { 4 + 2 y } { - 2 }$$

Whakaoti mō x

$$x=-2-\frac{6}{y}$$

$$y\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me whakarea ngā taha e rua o te whārite ki te 6, arā, te tauraro pātahi he tino iti rawa te kitea o 3,-2.

$$2\left(y-xy\right)=3\left(4+2y\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2 ki te y-xy.

$$2y-2yx=3\left(4+2y\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 3 ki te 4+2y.

$$2y-2yx=12+6y$$

Tangohia te 2y mai i ngā taha e rua.

$$-2yx=12+6y-2y$$

Pahekotia te 6y me -2y, ka 4y.

$$-2yx=12+4y$$

He hanga arowhānui tō te whārite.

$$\left(-2y\right)x=4y+12$$

Whakawehea ngā taha e rua ki te -2y.

$$\frac{\left(-2y\right)x}{-2y}=\frac{4y+12}{-2y}$$

Mā te whakawehe ki te -2y ka wetekia te whakareanga ki te -2y.

$$x=\frac{4y+12}{-2y}$$

Whakawehe 12+4y ki te -2y.

$$x=-2-\frac{6}{y}$$

Whakaoti mō y

$$y=-\frac{6}{x+2}$$

$$x\neq -2$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me whakarea ngā taha e rua o te whārite ki te 6, arā, te tauraro pātahi he tino iti rawa te kitea o 3,-2.

$$2\left(y-xy\right)=3\left(4+2y\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2 ki te y-xy.

$$2y-2yx=3\left(4+2y\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 3 ki te 4+2y.

$$2y-2yx=12+6y$$

Tangohia te 6y mai i ngā taha e rua.

$$2y-2yx-6y=12$$

Pahekotia te 2y me -6y, ka -4y.

$$-4y-2yx=12$$

Pahekotia ngā kīanga tau katoa e whai ana i te y.

$$\left(-4-2x\right)y=12$$

He hanga arowhānui tō te whārite.

$$\left(-2x-4\right)y=12$$

Whakawehea ngā taha e rua ki te -4-2x.

$$\frac{\left(-2x-4\right)y}{-2x-4}=\frac{12}{-2x-4}$$

Mā te whakawehe ki te -4-2x ka wetekia te whakareanga ki te -4-2x.

$$y=\frac{12}{-2x-4}$$

Whakawehe 12 ki te -4-2x.

$$y=-\frac{6}{x+2}$$