Whakaoti i te y+7/y-3=x

$$\frac { y + 7 } { y - 3 } = x$$

Whakaoti mō x

$$x=-\frac{y+7}{3-y}$$

$$y\neq 3$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia ngā taha e rua o te whārite ki te y-3.

$$y+7=x\left(y-3\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te x ki te y-3.

$$y+7=xy-3x$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$xy-3x=y+7$$

Pahekotia ngā kīanga tau katoa e whai ana i te x.

$$\left(y-3\right)x=y+7$$

Whakawehea ngā taha e rua ki te y-3.

$$\frac{\left(y-3\right)x}{y-3}=\frac{y+7}{y-3}$$

Mā te whakawehe ki te y-3 ka wetekia te whakareanga ki te y-3.

$$x=\frac{y+7}{y-3}$$

Whakaoti mō y

$$y=-\frac{3x+7}{1-x}$$

$$x\neq 1$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe y ki 3 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te y-3.

$$y+7=x\left(y-3\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te x ki te y-3.

$$y+7=xy-3x$$

Tangohia te xy mai i ngā taha e rua.

$$y+7-xy=-3x$$

Tangohia te 7 mai i ngā taha e rua.

$$y-xy=-3x-7$$

Pahekotia ngā kīanga tau katoa e whai ana i te y.

$$\left(1-x\right)y=-3x-7$$

Whakawehea ngā taha e rua ki te 1-x.

$$\frac{\left(1-x\right)y}{1-x}=\frac{-3x-7}{1-x}$$

Mā te whakawehe ki te 1-x ka wetekia te whakareanga ki te 1-x.

$$y=\frac{-3x-7}{1-x}$$

Whakawehe -3x-7 ki te 1-x.

$$y=-\frac{3x+7}{1-x}$$

Tē taea kia ōrite te tāupe y ki 3.

$$y=-\frac{3x+7}{1-x}\text{, }y\neq 3$$