Whakaoti i te frac{x-16x^{-1}}{5x}*(2-2x^-1-2x^-2/x^-1+4x^-2)

$$\frac { x - 16 x ^ { - 1 } } { 5 x } \cdot ( 2 - \frac { 2 x ^ { - 1 } - 2 x ^ { - 2 } } { x ^ { - 1 } + 4 x ^ { - 2 } } )$$

Aromātai

$$\frac{2\left(x-4\right)}{x^{2}}$$

Ngā Hipanga Rongoā Poto

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea i roto o \frac{x-16x^{-1}}{5x}.

$$\frac{\frac{1}{x}\left(x-4\right)\left(x+4\right)}{5x}\left(2-\frac{2x^{-1}-2x^{-2}}{x^{-1}+4x^{-2}}\right)$$

Hei whakawehe i ngā pū o te pūtake kotahi, tangohia te taupū o te taurunga i te taupū o te tauraro.

$$\frac{\left(x-4\right)\left(x+4\right)}{5x^{2}}\left(2-\frac{2x^{-1}-2x^{-2}}{x^{-1}+4x^{-2}}\right)$$

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea i roto o \frac{2x^{-1}-2x^{-2}}{x^{-1}+4x^{-2}}.

$$\frac{\left(x-4\right)\left(x+4\right)}{5x^{2}}\left(2-\frac{2\times \left(\frac{1}{x}\right)^{2}\left(x-1\right)}{\left(\frac{1}{x}\right)^{2}\left(x+4\right)}\right)$$

Me whakakore tahi te \left(\frac{1}{x}\right)^{2} i te taurunga me te tauraro.

$$\frac{\left(x-4\right)\left(x+4\right)}{5x^{2}}\left(2-\frac{2\left(x-1\right)}{x+4}\right)$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia 2 ki te \frac{x+4}{x+4}.

$$\frac{\left(x-4\right)\left(x+4\right)}{5x^{2}}\left(\frac{2\left(x+4\right)}{x+4}-\frac{2\left(x-1\right)}{x+4}\right)$$

Tā te mea he rite te tauraro o \frac{2\left(x+4\right)}{x+4} me \frac{2\left(x-1\right)}{x+4}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{\left(x-4\right)\left(x+4\right)}{5x^{2}}\times \frac{2\left(x+4\right)-2\left(x-1\right)}{x+4}$$

Mahia ngā whakarea i roto o 2\left(x+4\right)-2\left(x-1\right).

$$\frac{\left(x-4\right)\left(x+4\right)}{5x^{2}}\times \frac{2x+8-2x+2}{x+4}$$

Whakakotahitia ngā kupu rite i 2x+8-2x+2.

$$\frac{\left(x-4\right)\left(x+4\right)}{5x^{2}}\times \frac{10}{x+4}$$

Me whakarea te \frac{\left(x-4\right)\left(x+4\right)}{5x^{2}} ki te \frac{10}{x+4} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\frac{\left(x-4\right)\left(x+4\right)\times 10}{5x^{2}\left(x+4\right)}$$

Me whakakore tahi te 5\left(x+4\right) i te taurunga me te tauraro.

$$\frac{2\left(x-4\right)}{x^{2}}$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2 ki te x-4.

$$\frac{2x-8}{x^{2}}$$

Whakaroha

$$\frac{2\left(x-4\right)}{x^{2}}$$

Ngā Hipanga Rongoā Poto

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea i roto o \frac{x-16x^{-1}}{5x}.

$$\frac{\frac{1}{x}\left(x-4\right)\left(x+4\right)}{5x}\left(2-\frac{2x^{-1}-2x^{-2}}{x^{-1}+4x^{-2}}\right)$$

Hei whakawehe i ngā pū o te pūtake kotahi, tangohia te taupū o te taurunga i te taupū o te tauraro.

$$\frac{\left(x-4\right)\left(x+4\right)}{5x^{2}}\left(2-\frac{2x^{-1}-2x^{-2}}{x^{-1}+4x^{-2}}\right)$$

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea i roto o \frac{2x^{-1}-2x^{-2}}{x^{-1}+4x^{-2}}.

$$\frac{\left(x-4\right)\left(x+4\right)}{5x^{2}}\left(2-\frac{2\times \left(\frac{1}{x}\right)^{2}\left(x-1\right)}{\left(\frac{1}{x}\right)^{2}\left(x+4\right)}\right)$$

Me whakakore tahi te \left(\frac{1}{x}\right)^{2} i te taurunga me te tauraro.

$$\frac{\left(x-4\right)\left(x+4\right)}{5x^{2}}\left(2-\frac{2\left(x-1\right)}{x+4}\right)$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia 2 ki te \frac{x+4}{x+4}.

$$\frac{\left(x-4\right)\left(x+4\right)}{5x^{2}}\left(\frac{2\left(x+4\right)}{x+4}-\frac{2\left(x-1\right)}{x+4}\right)$$

Tā te mea he rite te tauraro o \frac{2\left(x+4\right)}{x+4} me \frac{2\left(x-1\right)}{x+4}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{\left(x-4\right)\left(x+4\right)}{5x^{2}}\times \frac{2\left(x+4\right)-2\left(x-1\right)}{x+4}$$

Mahia ngā whakarea i roto o 2\left(x+4\right)-2\left(x-1\right).

$$\frac{\left(x-4\right)\left(x+4\right)}{5x^{2}}\times \frac{2x+8-2x+2}{x+4}$$

Whakakotahitia ngā kupu rite i 2x+8-2x+2.

$$\frac{\left(x-4\right)\left(x+4\right)}{5x^{2}}\times \frac{10}{x+4}$$

Me whakarea te \frac{\left(x-4\right)\left(x+4\right)}{5x^{2}} ki te \frac{10}{x+4} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\frac{\left(x-4\right)\left(x+4\right)\times 10}{5x^{2}\left(x+4\right)}$$

Me whakakore tahi te 5\left(x+4\right) i te taurunga me te tauraro.

$$\frac{2\left(x-4\right)}{x^{2}}$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2 ki te x-4.

$$\frac{2x-8}{x^{2}}$$