Whakaoti i te x-1/x+1geq2

$$\frac { x - 1 } { x + 1 } \geq 2$$

Whakaoti mō x

$$x\in [-3,-1)$$

Ngā Upane Otinga

Kāore e taea a te tauraro x+1 te numa kore nā te mea kāore te rituatanga mā te kore e tautuhi. E rua ngā kēhi.

$$x+1>0 x+1<0$$

Whakaarohia te kēhi i ngā wā kei te tōrunga a x+1. Neke atu a 1 ki te taha matau.

$$x>-1$$

Kāore te tōrite tuatahi e whakarerekē te aronga ina e whakarea ana mā x+1 mō x+1>0.

$$x-1\geq 2\left(x+1\right)$$

Whakarea te katoa o te taha matau.

$$x-1\geq 2x+2$$

Neke atu ngā kīanga tau e whai ana i x ki te taha mauī me ētahi atu kupu katoa ki te taha matau.

$$x-2x\geq 1+2$$

Pahekotia ngā kīanga tau ōrite.

$$-x\geq 3$$

Whakawehea ngā taha e rua ki te -1. I te mea he tōraro a -1, ka huri te ahunga koreōrite.

$$x\leq -3$$

Whakaarohia te herenga x>-1 e tautuhi ana ki runga.

$$x\in \emptyset$$

Tēnā, me whakaarohia te tauira ina e tōraro a x+1. Neke atu a 1 ki te taha matau.

$$x<-1$$

E whakarerekē ana te aronga o te tōrite tuatahi hei ngā wā e whakarea ana a x+1 mō x+1<0.

$$x-1\leq 2\left(x+1\right)$$

Whakarea te katoa o te taha matau.

$$x-1\leq 2x+2$$

Neke atu ngā kīanga tau e whai ana i x ki te taha mauī me ētahi atu kupu katoa ki te taha matau.

$$x-2x\leq 1+2$$

Pahekotia ngā kīanga tau ōrite.

$$-x\leq 3$$

Whakawehea ngā taha e rua ki te -1. I te mea he tōraro a -1, ka huri te ahunga koreōrite.

$$x\geq -3$$

Whakaarohia te herenga x<-1 e tautuhi ana ki runga.

$$x\in [-3,-1)$$

Ko te otinga whakamutunga ko te whakakotahi i ngā otinga kua whiwhi.

$$x\in [-3,-1)$$