Whakaoti i te x/x-3+5x-1/x^2-3x=1

$$\frac { x } { x - 3 } + \frac { 5 x - 1 } { x ^ { 2 } - 3 x } = 1$$

Whakaoti mō x

$$x=\frac{1}{8}=0.125$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe x ki tētahi o ngā uara 0,3 nā te kore tautuhi i te whakawehenga mā te kore. Me whakarea ngā taha e rua o te whārite ki te x\left(x-3\right), arā, te tauraro pātahi he tino iti rawa te kitea o x-3,x^{2}-3x.

$$xx+5x-1=x\left(x-3\right)$$

Whakareatia te x ki te x, ka x^{2}.

$$x^{2}+5x-1=x\left(x-3\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te x ki te x-3.

$$x^{2}+5x-1=x^{2}-3x$$

Tangohia te x^{2} mai i ngā taha e rua.

$$x^{2}+5x-1-x^{2}=-3x$$

Pahekotia te x^{2} me -x^{2}, ka 0.

$$5x-1=-3x$$

Me tāpiri te 3x ki ngā taha e rua.

$$5x-1+3x=0$$

Pahekotia te 5x me 3x, ka 8x.

$$8x-1=0$$

Me tāpiri te 1 ki ngā taha e rua. Ko te tau i tāpiria he kore ka hua koia tonu.

$$8x=1$$

Whakawehea ngā taha e rua ki te 8.

$$x=\frac{1}{8}$$