Whakaoti i te x/b-2=c

$$\frac { x } { b } - 2 = c$$

Whakaoti mō b

$$\left\{\begin{matrix}b=\frac{x}{c+2}\text{, }&x\neq 0\text{ and }c\neq -2\\b\neq 0\text{, }&c=-2\text{ and }x=0\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe b ki 0 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te b.

$$x+b\left(-2\right)=cb$$

Tangohia te cb mai i ngā taha e rua.

$$x+b\left(-2\right)-cb=0$$

Tangohia te x mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$b\left(-2\right)-cb=-x$$

Pahekotia ngā kīanga tau katoa e whai ana i te b.

$$\left(-2-c\right)b=-x$$

He hanga arowhānui tō te whārite.

$$\left(-c-2\right)b=-x$$

Whakawehea ngā taha e rua ki te -2-c.

$$\frac{\left(-c-2\right)b}{-c-2}=-\frac{x}{-c-2}$$

Mā te whakawehe ki te -2-c ka wetekia te whakareanga ki te -2-c.

$$b=-\frac{x}{-c-2}$$

Whakawehe -x ki te -2-c.

$$b=\frac{x}{c+2}$$

Tē taea kia ōrite te tāupe b ki 0.

$$b=\frac{x}{c+2}\text{, }b\neq 0$$

Whakaoti mō c

$$c=\frac{x}{b}-2$$

$$b\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia ngā taha e rua o te whārite ki te b.

$$x+b\left(-2\right)=cb$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$cb=x+b\left(-2\right)$$

He hanga arowhānui tō te whārite.

$$bc=x-2b$$

Whakawehea ngā taha e rua ki te b.

$$\frac{bc}{b}=\frac{x-2b}{b}$$

Mā te whakawehe ki te b ka wetekia te whakareanga ki te b.

$$c=\frac{x-2b}{b}$$

Whakawehe x-2b ki te b.

$$c=\frac{x}{b}-2$$