Whakaoti i te x/7*14/x+9

$$\frac { x } { 7 } \cdot \frac { 14 } { x + 9 }$$

Aromātai

$$\frac{2x}{x+9}$$

Ngā Upane Otinga

Me whakarea te \frac{x}{7} ki te \frac{14}{x+9} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\frac{x\times 14}{7\left(x+9\right)}$$

Me whakakore tahi te 7 i te taurunga me te tauraro.

$$\frac{2x}{x+9}$$

Kimi Pārōnaki e ai ki x

$$\frac{18}{\left(x+9\right)^{2}}$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Otinga

Me whakarea te \frac{x}{7} ki te \frac{14}{x+9} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{x\times 14}{7\left(x+9\right)})$$

Me whakakore tahi te 7 i te taurunga me te tauraro.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{2x}{x+9})$$

Mō ngā pānga e rua e taea ana te pārōnaki, ko te pārōnaki o te otinga o ngā pānga e rua ko te tauraro whakareatia ki te pārōnaki o te taurunga tango i te taurunga whakareatia ki te pārōnaki o te tauraro, ā, ka whakawehea te katoa ki te tauraro kua pūruatia.

$$\frac{\left(x^{1}+9\right)\frac{\mathrm{d}}{\mathrm{d}x}(2x^{1})-2x^{1}\frac{\mathrm{d}}{\mathrm{d}x}(x^{1}+9)}{\left(x^{1}+9\right)^{2}}$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$\frac{\left(x^{1}+9\right)\times 2x^{1-1}-2x^{1}x^{1-1}}{\left(x^{1}+9\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{\left(x^{1}+9\right)\times 2x^{0}-2x^{1}x^{0}}{\left(x^{1}+9\right)^{2}}$$

Whakarohaina mā te āhuatanga tohatoha.

$$\frac{x^{1}\times 2x^{0}+9\times 2x^{0}-2x^{1}x^{0}}{\left(x^{1}+9\right)^{2}}$$

Hei whakarea pū o te pūtake ōrite, tāpiri ana taupū.

$$\frac{2x^{1}+9\times 2x^{0}-2x^{1}}{\left(x^{1}+9\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{2x^{1}+18x^{0}-2x^{1}}{\left(x^{1}+9\right)^{2}}$$

Pahekotia ngā kīanga tau ōrite.

$$\frac{\left(2-2\right)x^{1}+18x^{0}}{\left(x^{1}+9\right)^{2}}$$

Tango 2 mai i 2.

$$\frac{18x^{0}}{\left(x^{1}+9\right)^{2}}$$

Mō tētahi kupu t, t^{1}=t.

$$\frac{18x^{0}}{\left(x+9\right)^{2}}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$\frac{18\times 1}{\left(x+9\right)^{2}}$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$\frac{18}{\left(x+9\right)^{2}}$$