Whakaoti i te x/4x^2-12x+9-3x/9-4x^2

$$\frac { x } { 4 x ^ { 2 } - 12 x + 9 } - \frac { 3 x } { 9 - 4 x ^ { 2 } }$$

Aromātai

$$\frac{2x\left(4x-3\right)}{\left(2x+3\right)\left(2x-3\right)^{2}}$$

Ngā Hipanga Rongoā Poto

Tauwehea te 4x^{2}-12x+9. Tauwehea te 9-4x^{2}.

$$\frac{x}{\left(2x-3\right)^{2}}-\frac{3x}{\left(-2x-3\right)\left(2x-3\right)}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o \left(2x-3\right)^{2} me \left(-2x-3\right)\left(2x-3\right) ko \left(2x+3\right)\left(2x-3\right)^{2}. Whakareatia \frac{x}{\left(2x-3\right)^{2}} ki te \frac{2x+3}{2x+3}. Whakareatia \frac{3x}{\left(-2x-3\right)\left(2x-3\right)} ki te \frac{-\left(2x-3\right)}{-\left(2x-3\right)}.

$$\frac{x\left(2x+3\right)}{\left(2x+3\right)\left(2x-3\right)^{2}}-\frac{3x\left(-1\right)\left(2x-3\right)}{\left(2x+3\right)\left(2x-3\right)^{2}}$$

Tā te mea he rite te tauraro o \frac{x\left(2x+3\right)}{\left(2x+3\right)\left(2x-3\right)^{2}} me \frac{3x\left(-1\right)\left(2x-3\right)}{\left(2x+3\right)\left(2x-3\right)^{2}}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{x\left(2x+3\right)-3x\left(-1\right)\left(2x-3\right)}{\left(2x+3\right)\left(2x-3\right)^{2}}$$

Mahia ngā whakarea i roto o x\left(2x+3\right)-3x\left(-1\right)\left(2x-3\right).

$$\frac{2x^{2}+3x+6x^{2}-9x}{\left(2x+3\right)\left(2x-3\right)^{2}}$$

Whakakotahitia ngā kupu rite i 2x^{2}+3x+6x^{2}-9x.

$$\frac{8x^{2}-6x}{\left(2x+3\right)\left(2x-3\right)^{2}}$$

Whakarohaina te \left(2x+3\right)\left(2x-3\right)^{2}.

$$\frac{8x^{2}-6x}{8x^{3}-12x^{2}-18x+27}$$

Tauwehe

$$\frac{2x\left(4x-3\right)}{\left(2x+3\right)\left(2x-3\right)^{2}}$$