Whakaoti i te x/3+y/4=4;x/2-y/4=1

$$\frac { x } { 3 } + \frac { y } { 4 } = 4 ; \frac { x } { 2 } - \frac { y } { 4 } = 1$$

Whakaoti mō x, y

$$x=6$$

$$y=8$$

Ngā Upane e Whakamahi ana i te Whakakapinga

Whakaarohia te whārite tuatahi. Me whakarea ngā taha e rua o te whārite ki te 12, arā, te tauraro pātahi he tino iti rawa te kitea o 3,4.

$$4x+3y=48$$

Whakaarohia te whārite tuarua. Me whakarea ngā taha e rua o te whārite ki te 4, arā, te tauraro pātahi he tino iti rawa te kitea o 2,4.

$$2x-y=4$$

Hei whakaoti i ētahi whārite takirua mā te whakakapinga, me whakaoti tētahi whārite i te tuatahi mō tētahi o ngā taurangi. Ka whakakapi i te otinga mō taua taurangi ki tērā o ngā whārite.

$$4x+3y=48,2x-y=4$$

Kōwhiria tētahi o ngā whārite ka whakaotia mō te x mā te wehe i te x i te taha mauī o te tohu ōrite.

$$4x+3y=48$$

Me tango 3y mai i ngā taha e rua o te whārite.

$$4x=-3y+48$$

Whakawehea ngā taha e rua ki te 4.

$$x=\frac{1}{4}\left(-3y+48\right)$$

Whakareatia \frac{1}{4} ki te -3y+48.

$$x=-\frac{3}{4}y+12$$

Whakakapia te -\frac{3y}{4}+12 mō te x ki tērā atu whārite, 2x-y=4.

$$2\left(-\frac{3}{4}y+12\right)-y=4$$

Whakareatia 2 ki te -\frac{3y}{4}+12.

$$-\frac{3}{2}y+24-y=4$$

Tāpiri -\frac{3y}{2} ki te -y.

$$-\frac{5}{2}y+24=4$$

Me tango 24 mai i ngā taha e rua o te whārite.

$$-\frac{5}{2}y=-20$$

Whakawehea ngā taha e rua o te whārite ki te -\frac{5}{2}, he ōrite ki te whakarea i ngā taha e rua ki te tau huripoki o te hautanga.

$$y=8$$

Whakaurua te 8 mō y ki x=-\frac{3}{4}y+12. I te mea kotahi anake te taurangi kei te whārite i puta, ka taea e koe te whakaoti mō x hāngai tonu.

$$x=-\frac{3}{4}\times 8+12$$

Whakareatia -\frac{3}{4} ki te 8.

$$x=-6+12$$

Tāpiri 12 ki te -6.

$$x=6$$

Kua oti te pūnaha te whakatau.

$$x=6,y=8$$

Ngā Upane e Whakamahi ana i Ngā Poukapa

Whakaarohia te whārite tuatahi. Me whakarea ngā taha e rua o te whārite ki te 12, arā, te tauraro pātahi he tino iti rawa te kitea o 3,4.

$$4x+3y=48$$

Whakaarohia te whārite tuarua. Me whakarea ngā taha e rua o te whārite ki te 4, arā, te tauraro pātahi he tino iti rawa te kitea o 2,4.

$$2x-y=4$$

Tuhia ngā whārite ki te tānga ngahuru ka whakamahi i ngā poukapa hei whakaoti i te pūnaha o ngā whārite.

$$4x+3y=48,2x-y=4$$

Tuhia ngā whārite ki te tikanga tātai poukapa.

$$\left(\begin{matrix}4&3\\2&-1\end{matrix}\right)\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}48\\4\end{matrix}\right)$$

Whakarea mauī i te whārite ki te poukapa kōaro o \left(\begin{matrix}4&3\\2&-1\end{matrix}\right).

$$inverse(\left(\begin{matrix}4&3\\2&-1\end{matrix}\right))\left(\begin{matrix}4&3\\2&-1\end{matrix}\right)\left(\begin{matrix}x\\y\end{matrix}\right)=inverse(\left(\begin{matrix}4&3\\2&-1\end{matrix}\right))\left(\begin{matrix}48\\4\end{matrix}\right)$$

Ko te hua o tētahi poukapa me te kōaro ko te poukapa tuakiri.

$$\left(\begin{matrix}1&0\\0&1\end{matrix}\right)\left(\begin{matrix}x\\y\end{matrix}\right)=inverse(\left(\begin{matrix}4&3\\2&-1\end{matrix}\right))\left(\begin{matrix}48\\4\end{matrix}\right)$$

Whakareatia ngā poukapa kei te taha mauī o te tohu ōrite.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=inverse(\left(\begin{matrix}4&3\\2&-1\end{matrix}\right))\left(\begin{matrix}48\\4\end{matrix}\right)$$

Mō te poukapa 2\times 2 \left(\begin{matrix}a&b\\c&d\end{matrix}\right), ko te \left(\begin{matrix}\frac{d}{ad-bc}&\frac{-b}{ad-bc}\\\frac{-c}{ad-bc}&\frac{a}{ad-bc}\end{matrix}\right) te poukapa kōaro, nō reira ka taea te tuhi anō te whārite poukapa hei rapanga whakarea poukapa.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}-\frac{1}{4\left(-1\right)-3\times 2}&-\frac{3}{4\left(-1\right)-3\times 2}\\-\frac{2}{4\left(-1\right)-3\times 2}&\frac{4}{4\left(-1\right)-3\times 2}\end{matrix}\right)\left(\begin{matrix}48\\4\end{matrix}\right)$$

Mahia ngā tātaitanga.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}\frac{1}{10}&\frac{3}{10}\\\frac{1}{5}&-\frac{2}{5}\end{matrix}\right)\left(\begin{matrix}48\\4\end{matrix}\right)$$

Whakareatia ngā poukapa.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}\frac{1}{10}\times 48+\frac{3}{10}\times 4\\\frac{1}{5}\times 48-\frac{2}{5}\times 4\end{matrix}\right)$$

Mahia ngā tātaitanga.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}6\\8\end{matrix}\right)$$

Tangohia ngā huānga poukapa x me y.

$$x=6,y=8$$

Ngā Upane e Whakamahi i te Tangohanga

Whakaarohia te whārite tuatahi. Me whakarea ngā taha e rua o te whārite ki te 12, arā, te tauraro pātahi he tino iti rawa te kitea o 3,4.

$$4x+3y=48$$

Whakaarohia te whārite tuarua. Me whakarea ngā taha e rua o te whārite ki te 4, arā, te tauraro pātahi he tino iti rawa te kitea o 2,4.

$$2x-y=4$$

Hei whakaoti mā te tangohanga, ko ngā tau whakarea o tētahi o ngā taurangi me mātua ōrite i ngā whārite e rua kia whakakorehia ai te taurangi ina tangohia tētahi whārite mai i tētahi atu.

$$4x+3y=48,2x-y=4$$

Kia ōrite ai a 4x me 2x, whakareatia ngā kīanga tau katoa kei ia taha o te whārite tuatahi ki te 2 me ngā kīanga tau katoa kei ia taha o te whārite tuarua ki te 4.

$$2\times 4x+2\times 3y=2\times 48,4\times 2x+4\left(-1\right)y=4\times 4$$

Whakarūnātia.

$$8x+6y=96,8x-4y=16$$

Me tango 8x-4y=16 mai i 8x+6y=96 mā te tango i ngā kīanga tau ōrite i ia taha o te tohu ōrite.

$$8x-8x+6y+4y=96-16$$

Tāpiri 8x ki te -8x. Ka whakakore atu ngā kupu 8x me -8x, ka toe he whārite me tētahi taurangi kotahi ka taea te whakaoti.

$$6y+4y=96-16$$

Tāpiri 6y ki te 4y.

$$10y=96-16$$

Tāpiri 96 ki te -16.

$$10y=80$$

Whakawehea ngā taha e rua ki te 10.

$$y=8$$

Whakaurua te 8 mō y ki 2x-y=4. I te mea kotahi anake te taurangi kei te whārite i puta, ka taea e koe te whakaoti mō x hāngai tonu.

$$2x-8=4$$

Me tāpiri 8 ki ngā taha e rua o te whārite.

$$2x=12$$

Whakawehea ngā taha e rua ki te 2.

$$x=6$$

Kua oti te pūnaha te whakatau.

$$x=6,y=8$$