Whakaoti i te x/204/3a^2x=

$$\frac { x } { 20 } \frac { 4 } { 3 a ^ { 2 } x } =$$

Aromātai

$$\frac{1}{15a^{2}}$$

Ngā Upane Otinga

Me whakarea te \frac{x}{20} ki te \frac{4}{3a^{2}x} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\frac{x\times 4}{20\times 3a^{2}x}$$

Me whakakore tahi te 4x i te taurunga me te tauraro.

$$\frac{1}{3\times 5a^{2}}$$

Whakareatia te 3 ki te 5, ka 15.

$$\frac{1}{15a^{2}}$$

Kimi Pārōnaki e ai ki a

$$-\frac{2}{15a^{3}}$$

Ngā Upane e Whakamahi ana i te Ture Mekameka

Me whakarea te \frac{x}{20} ki te \frac{4}{3a^{2}x} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\frac{\mathrm{d}}{\mathrm{d}a}(\frac{x\times 4}{20\times 3a^{2}x})$$

Me whakakore tahi te 4x i te taurunga me te tauraro.

$$\frac{\mathrm{d}}{\mathrm{d}a}(\frac{1}{3\times 5a^{2}})$$

Whakareatia te 3 ki te 5, ka 15.

$$\frac{\mathrm{d}}{\mathrm{d}a}(\frac{1}{15a^{2}})$$

Mēnā ko F te hanganga o ngā pānga e rua e taea ana te pārōnaki f\left(u\right) me u=g\left(x\right), arā, mēnā ko F\left(x\right)=f\left(g\left(x\right)\right), ko te pārōnaki o F te pārōnaki o f e ai ki u whakareatia te pārōnaki o g e ai ki x, arā, \frac{\mathrm{d}}{\mathrm{d}x}(F)\left(x\right)=\frac{\mathrm{d}}{\mathrm{d}x}(f)\left(g\left(x\right)\right)\frac{\mathrm{d}}{\mathrm{d}x}(g)\left(x\right).

$$-\left(15a^{2}\right)^{-1-1}\frac{\mathrm{d}}{\mathrm{d}a}(15a^{2})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$-\left(15a^{2}\right)^{-2}\times 2\times 15a^{2-1}$$

Whakarūnātia.

$$-30a^{1}\times \left(15a^{2}\right)^{-2}$$

Mō tētahi kupu t, t^{1}=t.

$$-30a\times \left(15a^{2}\right)^{-2}$$