Whakaoti i te x/2y2/3xy^2

$$\frac { x } { 2 y } \frac { 2 } { 3 x y ^ { 2 } }$$

Aromātai

$$\frac{1}{3y^{3}}$$

Ngā Upane Otinga

Me whakarea te \frac{x}{2y} ki te \frac{2}{3xy^{2}} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\frac{x\times 2}{2y\times 3xy^{2}}$$

Me whakakore tahi te 2x i te taurunga me te tauraro.

$$\frac{1}{3yy^{2}}$$

Hei whakarea i ngā pū o te pūtake kotahi, me tāpiri ō rātou taupū. Tāpiria te 1 me te 2 kia riro ai te 3.

$$\frac{1}{3y^{3}}$$

Kimi Pārōnaki e ai ki y

$$-\frac{1}{y^{4}}$$

Ngā Upane e Whakamahi ana i te Ture Mekameka

Me whakarea te \frac{x}{2y} ki te \frac{2}{3xy^{2}} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\frac{\mathrm{d}}{\mathrm{d}y}(\frac{x\times 2}{2y\times 3xy^{2}})$$

Me whakakore tahi te 2x i te taurunga me te tauraro.

$$\frac{\mathrm{d}}{\mathrm{d}y}(\frac{1}{3yy^{2}})$$

Hei whakarea i ngā pū o te pūtake kotahi, me tāpiri ō rātou taupū. Tāpiria te 1 me te 2 kia riro ai te 3.

$$\frac{\mathrm{d}}{\mathrm{d}y}(\frac{1}{3y^{3}})$$

Mēnā ko F te hanganga o ngā pānga e rua e taea ana te pārōnaki f\left(u\right) me u=g\left(x\right), arā, mēnā ko F\left(x\right)=f\left(g\left(x\right)\right), ko te pārōnaki o F te pārōnaki o f e ai ki u whakareatia te pārōnaki o g e ai ki x, arā, \frac{\mathrm{d}}{\mathrm{d}x}(F)\left(x\right)=\frac{\mathrm{d}}{\mathrm{d}x}(f)\left(g\left(x\right)\right)\frac{\mathrm{d}}{\mathrm{d}x}(g)\left(x\right).

$$-\left(3y^{3}\right)^{-1-1}\frac{\mathrm{d}}{\mathrm{d}y}(3y^{3})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$-\left(3y^{3}\right)^{-2}\times 3\times 3y^{3-1}$$

Whakarūnātia.

$$-9y^{2}\times \left(3y^{3}\right)^{-2}$$