Whakaoti i te xsinx/1-x=y

$$\frac { x \sin x } { 1 - x } = y$$

Whakaoti mō y

$$y=-\frac{x\sin(x)}{x-1}$$

$$x\neq 1$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia ngā taha e rua o te whārite ki te -x+1.

$$x\sin(x)=y\left(-x+1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te y ki te -x+1.

$$x\sin(x)=-yx+y$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$-yx+y=x\sin(x)$$

Pahekotia ngā kīanga tau katoa e whai ana i te y.

$$\left(-x+1\right)y=x\sin(x)$$

He hanga arowhānui tō te whārite.

$$\left(1-x\right)y=x\sin(x)$$

Whakawehea ngā taha e rua ki te 1-x.

$$\frac{\left(1-x\right)y}{1-x}=\frac{x\sin(x)}{1-x}$$

Mā te whakawehe ki te 1-x ka wetekia te whakareanga ki te 1-x.

$$y=\frac{x\sin(x)}{1-x}$$