Whakaoti i te x^3/1+x^4

$$\frac { x ^ { 3 } } { 1 + x ^ { 4 } }$$

Kimi Pārōnaki e ai ki x

$$\left(\frac{x}{x^{4}+1}\right)^{2}\left(3-x^{4}\right)$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Otinga

Mō ngā pānga e rua e taea ana te pārōnaki, ko te pārōnaki o te otinga o ngā pānga e rua ko te tauraro whakareatia ki te pārōnaki o te taurunga tango i te taurunga whakareatia ki te pārōnaki o te tauraro, ā, ka whakawehea te katoa ki te tauraro kua pūruatia.

$$\frac{\left(x^{4}+1\right)\frac{\mathrm{d}}{\mathrm{d}x}(x^{3})-x^{3}\frac{\mathrm{d}}{\mathrm{d}x}(x^{4}+1)}{\left(x^{4}+1\right)^{2}}$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$\frac{\left(x^{4}+1\right)\times 3x^{3-1}-x^{3}\times 4x^{4-1}}{\left(x^{4}+1\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{\left(x^{4}+1\right)\times 3x^{2}-x^{3}\times 4x^{3}}{\left(x^{4}+1\right)^{2}}$$

Whakarohaina mā te āhuatanga tohatoha.

$$\frac{x^{4}\times 3x^{2}+3x^{2}-x^{3}\times 4x^{3}}{\left(x^{4}+1\right)^{2}}$$

Hei whakarea pū o te pūtake ōrite, tāpiri ana taupū.

$$\frac{3x^{4+2}+3x^{2}-4x^{3+3}}{\left(x^{4}+1\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{3x^{6}+3x^{2}-4x^{6}}{\left(x^{4}+1\right)^{2}}$$

Pahekotia ngā kīanga tau ōrite.

$$\frac{\left(3-4\right)x^{6}+3x^{2}}{\left(x^{4}+1\right)^{2}}$$

Tango 4 mai i 3.

$$\frac{-x^{6}+3x^{2}}{\left(x^{4}+1\right)^{2}}$$

Tauwehea te x^{2}.

$$\frac{x^{2}\left(-x^{4}+3x^{0}\right)}{\left(x^{4}+1\right)^{2}}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$\frac{x^{2}\left(-x^{4}+3\times 1\right)}{\left(x^{4}+1\right)^{2}}$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$\frac{x^{2}\left(-x^{4}+3\right)}{\left(x^{4}+1\right)^{2}}$$

Aromātai

$$\frac{x^{3}}{x^{4}+1}$$