Whakaoti i te x^2-x+9/x^3-9x+1/x^2-9-1/x-3+1/x

$$\frac { x ^ { 2 } - x + 9 } { x ^ { 3 } - 9 x } + \frac { 1 } { x ^ { 2 } - 9 } - \frac { 1 } { x - 3 } + \frac { 1 } { x }$$

Aromātai

$$\frac{1}{x+3}$$

Ngā Hipanga Rongoā Poto

Tauwehea te x^{3}-9x. Tauwehea te x^{2}-9.

$$\frac{x^{2}-x+9}{x\left(x-3\right)\left(x+3\right)}+\frac{1}{\left(x-3\right)\left(x+3\right)}-\frac{1}{x-3}+\frac{1}{x}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o x\left(x-3\right)\left(x+3\right) me \left(x-3\right)\left(x+3\right) ko x\left(x-3\right)\left(x+3\right). Whakareatia \frac{1}{\left(x-3\right)\left(x+3\right)} ki te \frac{x}{x}.

$$\frac{x^{2}-x+9}{x\left(x-3\right)\left(x+3\right)}+\frac{x}{x\left(x-3\right)\left(x+3\right)}-\frac{1}{x-3}+\frac{1}{x}$$

Tā te mea he rite te tauraro o \frac{x^{2}-x+9}{x\left(x-3\right)\left(x+3\right)} me \frac{x}{x\left(x-3\right)\left(x+3\right)}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{x^{2}-x+9+x}{x\left(x-3\right)\left(x+3\right)}-\frac{1}{x-3}+\frac{1}{x}$$

Whakakotahitia ngā kupu rite i x^{2}-x+9+x.

$$\frac{x^{2}+9}{x\left(x-3\right)\left(x+3\right)}-\frac{1}{x-3}+\frac{1}{x}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o x\left(x-3\right)\left(x+3\right) me x-3 ko x\left(x-3\right)\left(x+3\right). Whakareatia \frac{1}{x-3} ki te \frac{x\left(x+3\right)}{x\left(x+3\right)}.

$$\frac{x^{2}+9}{x\left(x-3\right)\left(x+3\right)}-\frac{x\left(x+3\right)}{x\left(x-3\right)\left(x+3\right)}+\frac{1}{x}$$

Tā te mea he rite te tauraro o \frac{x^{2}+9}{x\left(x-3\right)\left(x+3\right)} me \frac{x\left(x+3\right)}{x\left(x-3\right)\left(x+3\right)}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{x^{2}+9-x\left(x+3\right)}{x\left(x-3\right)\left(x+3\right)}+\frac{1}{x}$$

Mahia ngā whakarea i roto o x^{2}+9-x\left(x+3\right).

$$\frac{x^{2}+9-x^{2}-3x}{x\left(x-3\right)\left(x+3\right)}+\frac{1}{x}$$

Whakakotahitia ngā kupu rite i x^{2}+9-x^{2}-3x.

$$\frac{9-3x}{x\left(x-3\right)\left(x+3\right)}+\frac{1}{x}$$

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea i roto o \frac{9-3x}{x\left(x-3\right)\left(x+3\right)}.

$$\frac{3\left(-x+3\right)}{x\left(x-3\right)\left(x+3\right)}+\frac{1}{x}$$

Unuhia te tohu tōraro i roto o 3-x.

$$\frac{-3\left(x-3\right)}{x\left(x-3\right)\left(x+3\right)}+\frac{1}{x}$$

Me whakakore tahi te x-3 i te taurunga me te tauraro.

$$\frac{-3}{x\left(x+3\right)}+\frac{1}{x}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o x\left(x+3\right) me x ko x\left(x+3\right). Whakareatia \frac{1}{x} ki te \frac{x+3}{x+3}.

$$\frac{-3}{x\left(x+3\right)}+\frac{x+3}{x\left(x+3\right)}$$

Tā te mea he rite te tauraro o \frac{-3}{x\left(x+3\right)} me \frac{x+3}{x\left(x+3\right)}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{-3+x+3}{x\left(x+3\right)}$$

Whakakotahitia ngā kupu rite i -3+x+3.

$$\frac{x}{x\left(x+3\right)}$$

Me whakakore tahi te x i te taurunga me te tauraro.

$$\frac{1}{x+3}$$

Whakaroha

$$\frac{1}{x+3}$$

Ngā Hipanga Rongoā Poto

Tauwehea te x^{3}-9x. Tauwehea te x^{2}-9.

$$\frac{x^{2}-x+9}{x\left(x-3\right)\left(x+3\right)}+\frac{1}{\left(x-3\right)\left(x+3\right)}-\frac{1}{x-3}+\frac{1}{x}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o x\left(x-3\right)\left(x+3\right) me \left(x-3\right)\left(x+3\right) ko x\left(x-3\right)\left(x+3\right). Whakareatia \frac{1}{\left(x-3\right)\left(x+3\right)} ki te \frac{x}{x}.

$$\frac{x^{2}-x+9}{x\left(x-3\right)\left(x+3\right)}+\frac{x}{x\left(x-3\right)\left(x+3\right)}-\frac{1}{x-3}+\frac{1}{x}$$

Tā te mea he rite te tauraro o \frac{x^{2}-x+9}{x\left(x-3\right)\left(x+3\right)} me \frac{x}{x\left(x-3\right)\left(x+3\right)}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{x^{2}-x+9+x}{x\left(x-3\right)\left(x+3\right)}-\frac{1}{x-3}+\frac{1}{x}$$

Whakakotahitia ngā kupu rite i x^{2}-x+9+x.

$$\frac{x^{2}+9}{x\left(x-3\right)\left(x+3\right)}-\frac{1}{x-3}+\frac{1}{x}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o x\left(x-3\right)\left(x+3\right) me x-3 ko x\left(x-3\right)\left(x+3\right). Whakareatia \frac{1}{x-3} ki te \frac{x\left(x+3\right)}{x\left(x+3\right)}.

$$\frac{x^{2}+9}{x\left(x-3\right)\left(x+3\right)}-\frac{x\left(x+3\right)}{x\left(x-3\right)\left(x+3\right)}+\frac{1}{x}$$

Tā te mea he rite te tauraro o \frac{x^{2}+9}{x\left(x-3\right)\left(x+3\right)} me \frac{x\left(x+3\right)}{x\left(x-3\right)\left(x+3\right)}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{x^{2}+9-x\left(x+3\right)}{x\left(x-3\right)\left(x+3\right)}+\frac{1}{x}$$

Mahia ngā whakarea i roto o x^{2}+9-x\left(x+3\right).

$$\frac{x^{2}+9-x^{2}-3x}{x\left(x-3\right)\left(x+3\right)}+\frac{1}{x}$$

Whakakotahitia ngā kupu rite i x^{2}+9-x^{2}-3x.

$$\frac{9-3x}{x\left(x-3\right)\left(x+3\right)}+\frac{1}{x}$$

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea i roto o \frac{9-3x}{x\left(x-3\right)\left(x+3\right)}.

$$\frac{3\left(-x+3\right)}{x\left(x-3\right)\left(x+3\right)}+\frac{1}{x}$$

Unuhia te tohu tōraro i roto o 3-x.

$$\frac{-3\left(x-3\right)}{x\left(x-3\right)\left(x+3\right)}+\frac{1}{x}$$

Me whakakore tahi te x-3 i te taurunga me te tauraro.

$$\frac{-3}{x\left(x+3\right)}+\frac{1}{x}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o x\left(x+3\right) me x ko x\left(x+3\right). Whakareatia \frac{1}{x} ki te \frac{x+3}{x+3}.

$$\frac{-3}{x\left(x+3\right)}+\frac{x+3}{x\left(x+3\right)}$$

Tā te mea he rite te tauraro o \frac{-3}{x\left(x+3\right)} me \frac{x+3}{x\left(x+3\right)}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{-3+x+3}{x\left(x+3\right)}$$

Whakakotahitia ngā kupu rite i -3+x+3.

$$\frac{x}{x\left(x+3\right)}$$

Me whakakore tahi te x i te taurunga me te tauraro.

$$\frac{1}{x+3}$$