Aromātai
\frac{x^{2}-10}{x-\sqrt{10}}
Kimi Pārōnaki e ai ki x
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Tohaina
Kua tāruatia ki te papatopenga
\frac{\left(x^{2}-10\right)\left(x+\sqrt{10}\right)}{\left(x-\sqrt{10}\right)\left(x+\sqrt{10}\right)}
Whakangāwaritia te tauraro o \frac{x^{2}-10}{x-\sqrt{10}} mā te whakarea i te taurunga me te tauraro ki te x+\sqrt{10}.
\frac{\left(x^{2}-10\right)\left(x+\sqrt{10}\right)}{x^{2}-\left(\sqrt{10}\right)^{2}}
Whakaarohia te \left(x-\sqrt{10}\right)\left(x+\sqrt{10}\right). Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{\left(x^{2}-10\right)\left(x+\sqrt{10}\right)}{x^{2}-10}
Ko te pūrua o \sqrt{10} ko 10.
x+\sqrt{10}
Me whakakore tahi te x^{2}-10 i te taurunga me te tauraro.
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