Whakaoti i te x^2/4^2=39/13

$$\frac { x ^ { 2 } } { 4 ^ { 2 } } = \frac { 39 } { 13 }$$

Whakaoti mō x

$$x=4\sqrt{3}\approx 6.92820323$$

$$x=-4\sqrt{3}\approx -6.92820323$$

Ngā Upane mā te Kimi Pūtakerua

Tātaihia te 4 mā te pū o 2, kia riro ko 16.

$$\frac{x^{2}}{16}=\frac{39}{13}$$

Whakawehea te 39 ki te 13, kia riro ko 3.

$$\frac{x^{2}}{16}=3$$

Me whakarea ngā taha e rua ki te 16.

$$x^{2}=3\times 16$$

Whakareatia te 3 ki te 16, ka 48.

$$x^{2}=48$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=4\sqrt{3} x=-4\sqrt{3}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tātaihia te 4 mā te pū o 2, kia riro ko 16.

$$\frac{x^{2}}{16}=\frac{39}{13}$$

Whakawehea te 39 ki te 13, kia riro ko 3.

$$\frac{x^{2}}{16}=3$$

Tangohia te 3 mai i ngā taha e rua.

$$\frac{x^{2}}{16}-3=0$$

Whakareatia ngā taha e rua o te whārite ki te 16.

$$x^{2}-48=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -48 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-48\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-48\right)}}{2}$$

Whakareatia -4 ki te -48.

$$x=\frac{0±\sqrt{192}}{2}$$

Tuhia te pūtakerua o te 192.

$$x=\frac{0±8\sqrt{3}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±8\sqrt{3}}{2} ina he tāpiri te ±.

$$x=4\sqrt{3}$$

Nā, me whakaoti te whārite x=\frac{0±8\sqrt{3}}{2} ina he tango te ±.

$$x=-4\sqrt{3}$$

Kua oti te whārite te whakatau.

$$x=4\sqrt{3} x=-4\sqrt{3}$$